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3 years ago

Find the area of this figure.

Mathematics

2 answers:

kakasveta [241]3 years ago

5 0

Answer:

pretty sure it's 360 :)

Step-by-step explanation:

...

Novay_Z [31]3 years ago

5 0

Area = ( 1/2 × 4 × 3 ) + ( 1/2 × 5 × 6 )

Area = 6 + 15

Area = 21 ft^2

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What's -8 + (-1 1/8)

gogolik [260]

I think the answer is 9.375 if it needs to be in decimal form. If it needs to be in fraction form it would be improper, 9 3/8 would be the fraction. Hope it helps!

6 0

3 years ago

A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find

Ratling [72]

Answer:

Area of the garden:

$\begin{equation*} 398.93\text{ ft}^2 \end{equation*}$

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

$r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}$

Let's now go ahead and determine the area of the semicircle using the below formula;

$A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2$

Let's also determine the area of the rectangle;

$A_r=l*w=23*14=322\text{ ft}^2$

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

$\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}$

Therefore, the area of the garden is 398.93 ft^2

8 0

1 year ago

A long distance runner starts at the beginning of a trail and runs at a rate of 4 miles per hour. two hours later, a cyclist sta

valina [46]

To solve this problem, let us first assign variables. Let us say that:

A = runner

B = cyclist

d = distance

v = velocity

time = t

The time in which the cyclist overtakes the runner is the time wherein the distance of the two is the same, that is:

dA = dB

We know that the formula for calculating distance is:

d = v t

therefore,

vA tA = vB tB

Further, we know that tA = tB + 2, therefore:

vA (tB + 2) = vB tB

4 (tB + 2) = 14 tB

4 tB + 8 = 14 tB

10 tB = 8

tB = 0.8 hours = 48 min

Therefore the cyclist overtakes the runner after 0.8 hours or 48 minutes.

8 0

3 years ago

you send 12 photos to a company that makes personalized wall calendars the company enlarges the photos and inserts one for each

Assoli18 [71]

Answer:

15 inches

Step-by-step explanation:

We have that,

Length of the photo = 4 inches and Width of the photo = 6 inches

Also, the width of the image on the calendar = 10 inches

Let, the length on the image of the calendar = x inches.

Since, the ratio of the photo and its image will remain same, we get,

$\frac{4}{6}=\frac{10}{x}$

i.e. $x=\frac{60}{4}$

i.e. x = 15

Hence, the length of the image of the photo on the calendar is 15 inches.

3 0

3 years ago

Steffie makes a scale drawing for a crate with a scale factor of 1 to 3 the dimensions of her scale drawing are 15 inches long b

Evgen [1.6K]

Answer:

The length is 5 inches and the width is 4 inches

Step-by-step explanation:

Steffie makes a scale drawing for a crate with a scale factor of 1:3. The dimensions of her scale drawing are 15 inches long by 12 inches wide. The builder creates a scale drawing of the crate with a scale factor of 1:9. What are the dimensions of the builder's scale drawing? A. The length is 4 inches and the width is 5 inches B. The length is 45 inches and the width is 36 inches. C. The length is 5 inches and the width is 4 inches. D. The length is 36 inches and the width is 45 inches

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

dimensions of the image steffie scaled = (15 x 3) by (12 x 3) = 45 by 36

Builders scaled image = (45 / 9) by (36 /9) = 5 by 4

8 0

3 years ago