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2 years ago

Which statement is true regarding the functions on the

Mathematics

1 answer:

pychu [463]2 years ago

3 0

Answer:

<h2><em><u>Based on the given graph above, the statement that is considered true regarding the functions on the graph would be the first option: A) f(2) = g(2)</u></em></h2>

Step-by-step explanation:

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Expanded form using fractions 1/100

makkiz [27]

Answer:

Standard form: 1

Step-by-step explanation

expanded notation form: 1

expanded factors form: 1x1

expanded exponential for 1x 10^0

4 0

3 years ago

The two functions below are used to represent the height of a rocket above the ground after it is launched. which rocket reaches

Bess [88]

<span>The rocket that will reach a greater distance above the ground at its maximum height is y = -4x</span>² + 80x. The answer is letter B. This is because of the coefficient presented in the x² term. The number -4 is much greater than -6. Graphing these equations into a graphing paper or excel, you would get a parabola.

7 0

3 years ago

Which is the standard form of the equation of the parabola that has a vertex of (3, 1) and a directric of x = -2?

vagabundo [1.1K]

Check the picture below. So,the parabola looks like so, notice the distance "p". since the parabola is opening to the right, then "p" is positive, thus is 5.

$\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\$

$\bf -------------------------------\\\\
\begin{cases}
h=3\\
k=1\\
p=5
\end{cases}\implies (y-1)^2=4(5)(x-3)\implies (y-1)^2=20(x-3)
\\\\\\
\cfrac{1}{20}(y-1)^2=x-3\implies \boxed{\cfrac{1}{20}(y-1)^2+3=x}$

8 0

2 years ago

Read 2 more answers

Please help me it is an easy question

Ugo [173]

Answer:

200 yd²

Step-by-step explanation:

A = 17 yd

B = 15 yd

C = 2 yd

D = 8 yd

b) Area of rectangle = length * width

$\sf Area \ of \ 2 \ triangle = 2* \dfrac{1}{2}* base * height = base* height\\\\$

Area of right triangular prism = Areas of two triangle + area of the upper rectangle + area of middle rectangle + area of below rectangle

= 8 * 15 + 17 * 2 + 15 *2 + 8*2

= 120 + 34 + 30 + 16

= 200 yd²

5 0

1 year ago

Paul currently has $300 to spend on a data plan. He found a phone for $100 and a $50 a month charge.

zvonat [6]

Let x= months
So 50x is the total amount he pays after x months. You went to add 100 to this because there's a fixed cost of 100 for the phone
So you have the expression 100+50x which is the amount he pays after x months
Since he has a limit of 300,
100+50x < 300

3 0

2 years ago