Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :

For a square , 
⇒ 
⇒ 
⇒ 
⇒ 
Since length of diagonal (
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
y = 12x-6
Step-by-step explanation:
y=mx+b
y = 12x-6
Answer:
y=-1x+1
Step-by-step explanation:
Answer:
1250 pounds
Step-by-step explanation:
1625=x+30%
1625=1.3x
x=1250
1 because 1 times 1 times 1 equals 1