Question

Please help. Show all work:)

Answer 1

Answer:

  50

Step-by-step explanation:

$(3+\sqrt{-16})(6-\sqrt{-64})=(3+4\sqrt{-1})(6-8\sqrt{-1})=2(3+4\sqrt{-1})(3-4\sqrt{-1})\\\\=2(3^2-(4\sqrt{-1})^2)=2(9-(-16))\\\\=2(25)=50$

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We make use of the special form for the difference of squares:

  (a+b)(a-b) = a²-b²