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krek1111 [17]
3 years ago
8

Please help. Show all work:)

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

  50

Step-by-step explanation:

(3+\sqrt{-16})(6-\sqrt{-64})=(3+4\sqrt{-1})(6-8\sqrt{-1})=2(3+4\sqrt{-1})(3-4\sqrt{-1})\\\\=2(3^2-(4\sqrt{-1})^2)=2(9-(-16))\\\\=2(25)=50

__

We make use of the special form for the difference of squares:

  (a+b)(a-b) = a²-b²

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What is 31 in tens and ones
My name is Ann [436]
3 is in the tens and 1 is in the ones. To explain more easily... 30+1 is 31.<span />
5 0
3 years ago
Two points on L1 and two points on L2 are given. Use the slope formula to determine if lines L1 and L2 are parallel, perpendicul
vlada-n [284]

Answer:

The lines L1 and L2 neither parallel nor perpendicular

Step-by-step explanation:

* Lets revise how to find a slope of a line

- If a line passes through points (x1 , y1) and (x2 , y2), then the slope

 of the line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- Parallel lines have same slopes

- Perpendicular lines have additive, multiplicative slopes

 ( the product of their slopes is -1)

* Lets solve the problem

∵ L1 passes through the point (1 , 10) and (-1 , 7)

- Let (1 , 10) is (x1 , y1) and (-1 , 7) is (x2 , y2)

∴ x1 = 1 , x2 = -1 and y1 = 10 , y2 = 7

∴ The slope of L1 is m1 = \frac{7-10}{-1-1}=\frac{-3}{-2}=\frac{3}{2}

∵ L2 passes through the point (0 , 3) and (1 , 5)

- Let (0 , 3) is (x1 , y1) and (1 , 5) is (x2 , y2)

∴ x1 = 0 , x2 = 1 and y1 = 3 , y2 = 5

∴ The slope of L2 is m2=\frac{5-3}{1-0}=\frac{2}{1}=2

∵ m1 = 3/2 and m2 = 2

- The two lines have different slopes and their product not equal -1

∴ The lines L1 and L2 neither parallel nor perpendicular

7 0
3 years ago
Please can anyone send a question in law of indices I really need it now​
DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

(9^p)(27^q)=3^n\\

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

(9^p)(27^q)=3^n\\\\

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

(3^2)^p(3^3)^q=3^n\\

now we multiply p with 2 and

multiply q with 3 respectively,

(3^{2p})(3^{3q})=3^n\\

now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base

3^{2p+3q}=3^n\\

now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,

2p+3q=n\\

hence n is expressed in terms of p and q

Solution to part b)

if p = 1 and q = 2 we plug in these values in the above equation we found for n

n = 2p + 3q

n = 2(1) + 3(2)

n = 2 + 6

n = 7

6 0
3 years ago
3x/7 in verbal expression
FrozenT [24]
The answer to this equation in verbal expression would be 'the product of 3 and a number divided by 7'. I hope I helped!
7 0
3 years ago
Read 2 more answers
Need help with my homework plz
pav-90 [236]

Answer:

C. 17/20, rational

Step-by-step explanation:

.25 + 3/5

The least common denominator is 20 so

.25=1/4=5/20

3/5=12/20; therefore,

5/20 + 12/20=17/20.

17/20 is a fraction so is rational.

3 0
3 years ago
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