Question

A number cube with faces labeled from 1 to 6 was rolled 20 times. Each time the number

Answer 1

Answer:

0.4

Step-by-step explanation:

These are the relative frequencies of each face (data are missing in the text of the problem):

Number Showing  on Top Face   Frequency

1 0

2 3

3 3

4 6

5 3

6 5

The probability to obtain a certain number when throwing the dice is given by

$p(x_i)=\frac{f_i}{\sum f}$

where

$f_i$ is the relative frequency of the number $x_i$ to occur

$\sum f$ is the sum of the relative frequencies

Here the sum of the frequencies is:

$\sum f=0+3+3+6+3+5=20$

For number 5 here, we have:

$f_5 = 3$ (from the table)

So the probability of getting a 5 is

$p(5)=\frac{3}{20}$

For number 6 here, we have

$f_6=5$

So the probability of getting a 6 is

$p(6)=\frac{5}{20}$

So the probability to obtain either a 5 or a 6 in the next rolling is:

$p(5\cup 6)=p(5)+p(6)=\frac{3}{20}+\frac{5}{20}=\frac{8}{20}=0.4$