Answer:
its number d. my 1/8 brain cell said so.
Step-by-step explanation:
You can subtract 4x from each side of the equation.
Then you'll have the variable only on one side.
Before: 5x - 7 = 4x - 1
After: x - 7 = - 1
Now it's a lot easier to solve.
========================================
I just noticed that you're giving 10 points for this one.
That's a bunch, so I guess I owe you some more ...
I really ought to go ahead and finish the solution:
Original equation: 5x - 7 = 4x - 1
Subtract 4x from each side: x - 7 = - 1
Add 7 to each side: x = 6
(Once you subtracted 4x from each side,
there really wasn't much more left to do.)
I hope this helps you
x^2/3 [x^2/3.x^-1/4)^6.1/3.2
x^2/3[x^8-3/12]^4
x^2/3 [x^5/12]^4
x^2/3.x^5/12.4
x^2/3.x^5/3
x^2+5/3
x^7/3
Answer:
The data that we have is:
"Adrian's backyard pool contains 6.4 gallons of water. Adrian will begin filling his pool at a rate of 4.1 gallons per second."
Then we can write the amount of water in Adrian's pool as a linear function:
A(t) = 6.4gal + (4.1gal/s)*t
Where t is our variable and represents time in seconds.
We also know that:
"Dale's backyard pool contains 66.4 gallons of water. Dale will begin draining his pool at a rate of 0.9 gallons per second. "
We can also model this with a linear function:
D(t) = 66.4 gal + (0.9gal/s)*t
Both pools will have the same amount of water when:
D(t) = A(t)
So we can find the value of t:
6.4gal + (4.1gal/s)*t = 66.4 gal + (0.9gal/s)*t
(4.1gal/s)*t - (0.9gal/s)*t = 66.4gal - 6.4gal
(3.2gal/s)*t = 60gal
t = 60gal/(3.2gal/s) = 18.75s
In 18.75 seconds both pools will have the same amount of water.
