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inysia [295]
3 years ago
13

Cual es el resultado?

Mathematics
1 answer:
Korolek [52]3 years ago
5 0
I hope this helps you


x^2/3 [x^2/3.x^-1/4)^6.1/3.2


x^2/3[x^8-3/12]^4


x^2/3 [x^5/12]^4


x^2/3.x^5/12.4


x^2/3.x^5/3


x^2+5/3


x^7/3
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It is on he other side of the #
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Find the value of k if: (2x − y) 2 − (2x + y) 2 = 4xyk<br>​
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Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student
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Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

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M(\frac{x1+x2}{2},\frac{y1+y2}{2})

<u><em>Verify the midpoint of each student</em></u>

student 1

we have the endpoints

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substitute in the formula

M(\frac{-9+11}{2},\frac{0-8}{2})

M(1,-4)

so

The midpoint is not (-1,4)

student 2

we have the endpoints

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substitute in the formula

M(\frac{-6+4}{2},\frac{-1-7}{2})

M(-1,-4)

so

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student 3

we have the endpoints

(-5,2) and (3,6)

substitute in the formula

M(\frac{-5+3}{2},\frac{2+6}{2})

M(-1,4)

so

<u>The midpoint is equal to (-1,4)</u>

student 4

we have the endpoints

(-3,10) and (5,-2)

substitute in the formula

M(\frac{-3+5}{2},\frac{10-2}{2})

M(1,4)

so

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student 5

we have the endpoints

(0,-3) and (-2,11)

substitute in the formula

M(\frac{0-2}{2},\frac{-3+11}{2})

M(-1,4)

so

<u>The midpoint is equal to (-1,4)</u>

therefore

Student 3 and student 5

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