Answer:
the length of JM is 11x + 40
Step-by-step explanation:
<span>It is
12000 x (1.06)^12 + 50000 x (1.06)^6
= 95,072.31
start of 4th year to end of 6th year = 6 semi-annual periods where interest is compounded for the second deposit</span>
Answer:
=50x2−1400x+4800
Step-by-step explanation: