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adelina 88 [10]
2 years ago
8

Which functions have real zeros at 1 and 4? Check all that apply

Mathematics
1 answer:
yuradex [85]2 years ago
6 0
X^2 - 5x + 4
-2x^2 + 10x -8
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Find the percent of increase from 40 gallons to 89 gallons. Round to the nearest tenth of a percent if necessary.
tiny-mole [99]

Answer:

50

Step-by-step explanation:

because 89-49=49 49 rouded to the nearest ten is 50

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%
Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx

Replace x \to x^{\frac1\phi} = x^{\phi-1} :

I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

Split the integral at x = 1. For the integral over [1, ∞), substitute x \to \frac1x :

\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

The integrals involving tan⁻¹ disappear, and we're left with

I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}

8 0
2 years ago
Domain and range of y=6 + -2​
g100num [7]

The domain is negative infinity to positive infinity and the range is 8.

6 0
3 years ago
PLS HELP WILL MARK BRAINLIEST
ahrayia [7]
9(2j+7+5j) Foil this out to get 18j+7+45j then 63j+7

Answer: 18j+7+45j , 63j+7 I think
8 0
2 years ago
Read 2 more answers
!!!*BRAINLIEST*!!!
QveST [7]

Answer:

A

Step-by-step explanation:

Area = length times height times width

Area = 164 x 82 x 9.8

= 131790.4

Multiply by 7.48 since it takes 7.48 gallons to fill a cubic foot then you find the answer of A.

8 0
2 years ago
Read 2 more answers
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