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Ne4ueva [31]
3 years ago
8

Is the area usually bigger than the perimeter in an object?

Mathematics
2 answers:
qaws [65]3 years ago
8 0
USUALLY that is the case. But you can't say for sure.

For example: say the radius of a circle is 1m.
Perimeter = 2πR = 2*3.14*1 = 6.28m
Area = πR² = 3.14*1² = 3.14 m²
Here the numerical value of Perimeter is more than the numerical value of area.

Hope it helps!
anastassius [24]3 years ago
4 0
Hope it helps u out have a great day

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F (x) = x^2 + 2x - 5<br> g(x) = 2x + 4<br> What is (f• g)(x)?
Vilka [71]

Answer:

Step-by-step explanation:

This is a composite function, f(g(x)). This means, working from the inside function to the outside, we will take the function g and plug it in for x in the f function. g(x) = 2x + 4. We will plug that into f(x) and evaluate f(2x+4):

f(g(x))=(2x+4)^2+2(2x+4)-5 and I imagine your teacher has you simplify completely. We FOIL and distribute to get

f(g(x))=4x^2+16x+16+4x+8-5 which, by combining like terms, give us

f(g(x))=4x^2+20x+19

5 0
3 years ago
The work of a student to solve the equation 2(5y – 2) = 12 + 6y is shown below: Step 1: 2(5y – 2) = 12 + 6y Step 2: 7y – 4 = 12
kirza4 [7]
2(5y - 2) = 12 + 6y
7y - 4 = 12 + 6y ⇒ wrong, it has to be: 10y - 4 = 12 + 6y

so the correct answer is B 
7 0
3 years ago
Read 2 more answers
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MariettaO [177]

Answer:

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8 0
3 years ago
Compare and contrast the solution of |2x + 8| &gt; 6 and the solution of |2x + 8| &lt; 6.
svet-max [94.6K]

Answer:

B.

The solution of |2x + 8| > 6 includes all values that are less than –7 or greater than –1.

The solution of |2x + 8| < 6 includes all values that are greater than –7 and less than –1.

__

Step-by-step explanation:

You can find the solution by "unfolding" the absolute value, then dividing by 2 and subtracting 4:

-6 > 2x +8 > 6 . . . . . read this as -6 is less than 2x+8 or 2x+8 is greater than 6

-3 > x +4 > 3 . . . . . . .divide by 2

-7 > x > -1 . . . . . . . . . solution to the first inequality: x is less than -7 or greater than -1.

___

The solution to the other inequality is identical, except the direction of the comparison is reversed. It is read differently, because the segments overlap, rather than being disjoint.

-7 < x < -1 . . . . . . . . solution to the second inequality: x is greater than -7 and less than -1.

__

These descriptions match choice B.

3 0
3 years ago
Angles formed by Parallel lines 8th grade
pashok25 [27]
None since parallel lines never intersect.


I hope this helps! 
6 0
3 years ago
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