Which civilization believed in one god? a : babylonians b : egyptians c : hebrews d : phoenicians

Mathematics

2 answers:

Radda [10]2 years ago

5 0

The Hebrews were the only civilization who believed one God.

Kay [80]2 years ago

3 0

The answer is Hebrews. You can find this in Mark 12:29 in the King James Version of the Holy Bible.

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Answer the questions below about the quadratic function.

Korolek [52]

Given the function $f(x)=3x^2-18x+23$ . The above function can be written as

$f(x)=3x^2-18x+23\\ f(x)=3(x^2-6x)+23\\ f(x)=3(x^2-6x+9-9)+23\\ f(x)=3(x-3)^2-27+23\\ f(x)=3(x-3)^2-4$

a)Now, the function $f(x)=3(x-3)^2-4$ has minimum value since the coefficient of $(x-3)^2$ is $3>0$ .

b) The minimum value of the function occurs at $x=3$ and its value is

$f(3)=3(3-3)^2-4 =-4$

c)The minimum value of the function occurs at $x=3$ .

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3 years ago

Three numbers add up to 180. The second number is twice the first, and the third number is three times the first. WHAT IS EACH N

Ratling [72]

The answer is 30,60,90. Because 60 is twice the number 30 and 90 is three times the first number.

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3 years ago

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3 years ago

The graph of which function will have a maximum and a y-intercept of 4? f(x) = 4x2 + 6x – 1 f(x) = –4x2 + 8x + 5 f(x) = –x2 + 2x

V125BC [204]

Answer:

Option C (f(x) = $-x^2 + 2x + 4$ )

Step-by-step explanation:

In this question, the first step is to write the general form of the quadratic equation, which is f(x) = $ax^2 + bx + c$ , where a, b, and c are the arbitrary constants. There are certain characteristics of the values of a, b, and c which determine the nature of the function. If a is a positive coefficient (i.e. if a>0), then the quadratic function is a minimizing function. On the other hand, a is negative (i.e. if a<0), then the quadratic function is a maximizing function. Since the latter condition is required, therefore, the first option (f(x) = $4x^2 + 6x - 1$ ) and the last option (f(x) = $x^2 + 4x - 4$ ) are incorrect. The features of the values of b are irrelevant in this question, so that will not be discussed here. The value of c is actually the y-intercept of the quadratic equation. Since the y-intercept is 4, the correct choice for this question will be Option C (f(x) = $-x^2 + 2x + 4$ ). In short, Option C fulfills both the criteria of the function which has a maximum and a y-intercept of 4!!!