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Mandarinka [93]
3 years ago
9

Write the expression in its written form. 3/8×(1−13)

Mathematics
1 answer:
kaheart [24]3 years ago
4 0

Answer:

7 /8

0.875

Step-by-step explanation:

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The perimeter of a quarter circle is 10. 71 yards. What is the quarter circle's radius?
Ahat [919]

Answer:

r = 3 yds

Step-by-step explanation:

The perimeter of a quarter circle is 1/4 of a circumference of the circle AND two straight edges that are the length of the radius. see image.

The circumference is given and using 3.14 for pi, we'll then solve for r. see image.

4 0
2 years ago
-2<img src="https://tex.z-dn.net/?f=-2%20divided%20by%28-2%29" id="TexFormula1" title="-2 divided by(-2)" alt="-2 divided by(-2)
sergij07 [2.7K]

Answer:

1

Step-by-step explanation:

6 0
3 years ago
Let f(x) = 8x^3 − 22x^2 − 4 and g(x) = 4x − 3. Find f(x) over g(x).
Alenkasestr [34]
You would use the long division technique..

Here it looks like:
<span>
            --------------------
4x − 3 |</span> <span>8x^3 − 22x^2 − 4
---------
           |</span>
           |
<span>           |

and like that,,,

after you do this, you will get

2x^2-4x-3-\frac{13}{4x-3}


hope that helps
</span>
5 0
3 years ago
A box with no top is to be constructed from a piece of cardboard whose length measures 5 in. more than its width. The box is to
ddd [48]

Answer:

9\text{ inch, }14\text{ inch, }2\text{ inch}

Step-by-step explanation:

GIVEN: A box with no top is to be constructed from a piece of cardboard whose length measures 5\text{ inch} more than its width. The box is to be formed by cutting squares that measure 2\text{ inch} on each side from the four corners and then folding up the sides.

TO FIND: If the volume of the box will be 100\text{ inch}^3​, what are the dimensions of the piece of​ cardboard.

SOLUTION:

Let the width of cardboard be x

length of cardboard =x+5\text{ inch}

As box is formed by cutting 2\text{ inch } squares from corners of cardboard

length of cardboard =x+5-4=x+1\text{ inch}

width of cardboard  =x-4\text{ inch}

height of cardboard =2\text{ inch}

volume of cardboard =\text{length}\times\text{width}\times\text{height}

                                   =2(x+1)(x-4)

x^2-3x-54=0

solving we get

x=9,-6

width of cardboard =9\text{ inch}

length of cardboard =x+5=14\text{ inch}

height of cardboard =2\text{ inch}

8 0
3 years ago
student tickets for the football game cost $12 each and adult ticket cost $20 $1,720 was collected for the 120 ticket sold at la
erik [133]

Answer:

85 student tickets and 35 adult tickets were sold.

Step-by-step explanation:

Howdy!

We know that student tickets cost $12, adult ticket cost $20 and 120 tickets were sold.

So:

$12×A + $20×B = $1,720. Where A and B are the number of student tickets and adult tickets sold, respectively.

Given that 120 tickets were sold in total, we have that:

A + B = 120

So the system of equations to be solved is the following:

$12×A + $20×B = $1,720                    (1)

A + B = 120                                          (2)

Solving for 'A' in equation (2) we get:

A = 120 - B

Substituting this value into equation (1) we get:

$12×(120 - B) + $20×B = $1,720

Solving for 'B' we have:

$12×(120 - B) + $20×B = $1,720

$1,440 - $12×B + $20×B = $1,720

$1,440 + $8×B = $1,720

$8×B = $1,720 - $1,440

$8×B = $280

B = 35 tickets.

Given that B = 35, then A = 120 - 35 = 85 tickets.

So 85 student tickets and 35 adult tickets were sold.

4 0
3 years ago
Read 2 more answers
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