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Marysya12 [62]
3 years ago
6

Which one is > greater or < less than or = equal to?? 6+√8____√6+8​

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

\huge\boxed{\sqrt{6}+8\;is\;greater\;than \;6+\sqrt{8}  }

6+\sqrt[]{8} =8.82\\\sqrt{6}+8=10.44\\\\\boxed{Therefore, \sqrt{6}+8\;is\;greater\;than\;6+\sqrt{8}. }

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The answer will be v=7
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What is the equation of its axis of symmetry?
sleet_krkn [62]

Answer:

x=-7

Step-by-step explanation:

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Which of the following is not a requirement of a standard form equation Ax+By=C? a)A ≥ 0. b)B ≥ 0. c)A and B are not both 0. d)A
Ghella [55]
<h2>Answer:</h2>

The following which is not a requirement of a standard form of equation Ax+By=C is:

        b)   B ≥ 0    

<h2>Step-by-step explanation:</h2>

We know that the standard equation of a line is given by:

        Ax+By=C

where A,B and C are integers and A is taken to be a non-negative integer i.e. (A≥0) also the greatest common factor of A,B and C is: 1.

Also A and B can't be both zero.

       Hence, the correct option is:

                Option: b

7 0
3 years ago
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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

\mu = 55.5 + 0.5\sigma

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

6 0
2 years ago
Mike took clothes to the cleaners three times last month.​ First, brought 4 shirts and of slacks and paid ​$11.45. Then brought
GenaCL600 [577]

Complete Question:

Mike took clothes to the cleaners three times last month.​ First, brought 4 shirts and 1 pair of slacks and paid ​$11.45. Then brought ​7 shirts, 2 pairs of​ slacks, and 2 sports and paid ​$35.39. ​Finally, brought 5 shirts and 2 sports and paid ​$21.43 . How much was charged for each​ shirt, each pair of​ slacks, and each sports​ coat?

Answer:

The charges

For each Shirt = $1.49

For each pair of slacks = $5.49

For each sports coat = $6.99

Step-by-step explanation:

Let Shirt = a

Let pair of slacks = b

Let sports coat = c

First, brought 4 shirts and 1 pair of slacks and paid ​$11.45

= 4a + b = 11.45 ..........Equation 1

b = 11.45 - 4a

Then brought ​7 shirts, 2 pairs of​ slacks, and 2 sports and paid ​$35.39

= 7a + 2b + 2c = 35.39.........Equation 2

5 shirts and 2 sports and paid ​$21.43

5a + 2c = 21.43............Equation 3

Hence:

4a + b = 11.45 ..........Equation 1

7a + 2b + 2c = 35.39.........Equation 2

Using elimination method

Multiply Equation 2 by the coefficient of b = 1 in Equation 1

Multiply Equation 1 by the coefficient of b = 2 in Equation 2

8a + 2b = 22.9 .......Equation 4

7a + 2b + 2c = 35.39.........Equation 2

Subtracting Equation 2 from Equation 4

= a - 2c = -12.49 ........Equation 5

a = -12.49 + 2c

Subtituting -12.49 + 2c for a in Equation 3

5a + 2c = 21.43............Equation 3

5(-12.49 + 2c) + 2c = 21.43

= -62.45 + 10c + 2c = 21.43

Collecting like terms

10c + 2c = 21.43 + 62.45

12c = 83.88

c = 83.88/12

c = 6.99

5a + 2c = 21.43............Equation 3

Substituting 6.99 for c in Equation 3

5a + 2(6.99) = 21.43

5a + 13.98 = 21.43

5a = 21.43 - 13.98

5a = 7.45

a = 7.45/5

a = 1.49

4a + b = 11.45 ..........Equation 1

Substituting 1.49 for a in Equation 1

4(1.49) + b = 11.45

b = 11.45 - 4(1.49)

b = 11.45 - 5.96

b = 5.49

Therefore, since the charges

For each shirt = a

The charges for each Shirt = $1.49

For each pair of slacks = b

The charges for each pair of slacks = $5.49

For each sports coat = c

The charges for each sports coat = $6.99

3 0
3 years ago
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