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Nadusha1986 [10]
3 years ago
11

Muriel purchases a new car for $25,000. The car's value can be modeled by the following exponential function: y = 25000(0.84)^t

where y represents the car's value and t represents time in years. What is the decay rate expressed as a percentage?
Mathematics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

16%

Step-by-step explanation:

if you do 1-0.84 it equals .16 & .16 as a percentage is 16% so it is decaying at a rate of 16%

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Answer: c the third option

Step-by-step explanation:

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1. What are the first five terms of the sequence given by the formula an = 5n + 1?
Dvinal [7]

The correct answers are:

(1) 6, 11, 16, 21, 26 (Option B)

(2)~a_1 = 8; ~a_n = a_{n-1} - 2~ (Option A)

(3)~a_n = -2 + 3(n-1)~~~~ (Option D)

Explanations:

(1) Given Sequence:

a_n = 5n + 1

Now in order to find the first 5 terms, we need to put n=1,2,3,4,5 in the above sequence and solve.

For n=1: a_1 = 5(1) + 1 = 6

For n=2: a_2 = 5(2) + 1 = 11

For n=3: a_3 = 5(3) + 1 = 16

For n=4: a_4 = 5(4) + 1 = 21

For n=5: a_5 = 5(5) + 1 = 26

Hence, the first five terms are: 6, 11, 16, 21, 26 (Option B)

(2) Given Sequence:

8, 6, 4, 2, …

Now to find the recursive definition, we need to adopt trial-and-error approach.

As, a_1 = 8 (meaning the first element of the sequence is 8), the second or nth value of the sequence can be found by using the following formula:

a_n = a_{n-1} - d --- (1)

Where, n = the index of the number in a sequence

d = difference between two consecutive numbers = 8-6 = 2

Now,

The second number of the sequence has to be 6 by using (1). Put n = 2 and d = 2 in (1):

a_2 = a_{2-1} - 2

a_2 = a_{1} - 2

Since a_1 = 8, therefore,

a_2 = 8 - 2 = 6 (correct)

Hence the correct answer is a_1 = 8; ~a_n = a_{n-1} - 2~ (Option A)

(3) Given Sequence:

−2, 1, 4, 7, …

To find the explicit definition, use the following formula:

a_n = a_1 + (n-1)*d --- (X)

Where,

a_n = nth~term~of~the~sequence \\a_1 = 1st~term~of~the~sequence = -2 \\d = common~difference = 4-1 = 7-4 = 3 \\n = index~of~a~number~in~a~sequence \\

Plug in the values in (X):

(X)=> a_n = -2 + (n-1)*3~~~~ (Option D)

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