In order to solve this problem, we must solve an equation.
First, we need to define our unknown.
Let's call our number "n".
So, the sum of the number and 6 is the same as saying n+6
Then we need to multiply it by 2 (since it's twice the sum)
2(n+6)
This whole thing is equal to three times of the difference of the number and 8
n-8 is equal to the difference between the number and 8, then we need to multiply it by three.
3(n-8)
now, we set both sides equal and solve
The number is 36
Answer:
2. 10
3. D. 1 for all n
Step-by-step explanation:
2. The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^b = 1/a^-b
__
The value of n is 10.
__
3. Using the above rules of exponents, the expression simplifies to ...
6^(-n+n) = 6^0 = 1
The value is 1 for any n.
Explanation:
250 can be used as a total, with 10 being how much something subtracted multiple times takes away, and 20 being the end result. So, we could make the problem about a lot of things, but I'll go ahead and write the first one that comes to mind.
Answer:
Arata has $250 in his bank account, and plans on buying several CDs. Each one costs $10, and by the end of the trip, there is only $20 left in his account. How many CDs did Arata buy, assuming there was no tax or other additional charges?
Mary bought 4 apples at $8
so unit price = 8/4 = $2/each
Table:
Apples Price
1 $2
3 $6
4 $8
7 $14
