What is the solution to 2sin^(2)x+sinx+1=0

1 answer:

3 0

Well you can try rewriting it to this

answer is d 270

first start of by factoring and subtracting the 1 into the right side

sin(x) ( 2 sin (x) + 1) = -1

set each one equal to -1

sin( x) = -1 and 2 sin (x) +1 = -1

2 sin (x) = -2
sin ( x) = -1
so therefore we have our final equation

sin ( x ) = - 1 and sin (x) = -1

so then you look in your unit circle and find what coordinate equals -1 in terms of sin x

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Hello from MrBillDoesMath!

Answer:

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Where do the lines intersect?

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Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .