Question

What is the solution to 2sin^(2)x+sinx+1=0

Answer 1

Well you can try rewriting it to this

answer is   d  270

first start of by factoring  and subtracting the 1 into the right side

sin(x)  ( 2 sin (x)  + 1)  = -1  

set each one equal to -1 

sin( x) = -1   and   2 sin (x) +1 =  -1 

                              2 sin (x) = -2
                               sin ( x) = -1 
so therefore we have our final equation

sin ( x )  = - 1  and sin (x) = -1 

so then you look in your unit circle and find what coordinate equals -1 in terms of sin x