Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
The solution of the equation are as follows:
x = 6 and y = -5
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<h3>How to solve the system of equation?</h3>
4x + 5y = -1
-5x - 8y = 10
Therefore,
20x + 25y = -5
-20x - 32y = 40
-7y = 35
y = -5
Hence,
4x + 5(-5) = -1
4x - 25 = -1
4x = -1 + 25
4x = 24
x = 24 / 4
x = 6
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(5) Angle ADC is the sum of angles ADB and BDC.
(6) Yes, because lines AG and EC form two pairs of vertical angles, including ADC and EDG, as well as ADE and CDG.
(7) Angle HJK is clearly a right angle, and a right angle has measure 90°.
Answer:
A is 10 and B is 35
Step-by-step explanation:
multiply the width or length by 1.25
We are given the expanded form and we need to write the standard form:
10 + 8x(1/10) + 3 x(1/100) + 9 x (1/1000)
So, that is:
10 + 0.8 + 0.03 + 0.009
= 10.839
