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user100 [1]
4 years ago
13

What is thirty-five times fifty

Mathematics
1 answer:
Varvara68 [4.7K]4 years ago
6 0

Answer:

1750

Step-by-step explanation:

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Two sides of a right triangle measure 2 units and 4 units.
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20

Step-by-step explanation:

using pythagorean theorem to find the hypotenuse gives √20, so the measure of the side of the square is also √20, square that to give the area of square, which is 20

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Divide. Write your answer in simplest form. −8/9÷(−8/9)=
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Answer:

-  \frac{8}{9}  \div  ( - \frac{8}{9} ) \\  -  \frac{8}{9}   \times  ( -  \frac{9}{8} ) \\  = 1

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Cual es el resultado al realizar la siguiente operacion 4/9*2/5*3 2/4?
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0.62222222222

Step-by-step explanation:

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3 years ago
The drama club is selling tickets to its play. An adult ticket costs $15 and a student tickets costs $11. The auditorium will se
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Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
3 years ago
Read 2 more answers
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