1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Step-by-step explanation:
<u>1. 5 in and 1/3 in</u>
Here,

<u>2. 5 in and 4/3 in</u>
Here,

<u>3. 5/2 in and 4/3 in</u>

<u>4. 7/6 in and 6/7 in</u>
<u>Let</u>

<u>Hence,</u>
1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Keywords: Rectangle, Area
Learn more about rectangles at:
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To solve this problem, you must find a common denominator. First, you multiply the denominators together, then, multiply the numerator of the first fraction by the original denominator of the second fraction and vis-versa.
<span>3*4 = denominator of both
</span><span>2*4 = numerator of first fraction
</span><span>3*3 = numerator of second fraction
</span>
Your fractions should end up being 8/12 cups of raisins and 9/12 cup of almonds. You can now compare these fractions.
<span>Overall, there are 1/12 more almonds than raisins.</span>
The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
The father hippo weighs 6,204 pounds.
You subtract the weight of the other hippos from the total weight of the family to get this.
Answer:
$200
Step-by-step explanation:
4 different streets with 5 customers on each means 4*5 customers or 20 customers. If he has 20 customers and he gets $10 from each one, thats 20*10. he collected $200