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Lemur [1.5K]
3 years ago
7

How to model fractions

Mathematics
1 answer:
Feliz [49]3 years ago
7 0
You just take your bottom number and break a box into that many parts then fill in how ever many boxes the top number is

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Simplify the expression: 2(x+h)^2 - 2x^2 over (x+h) - x
Karolina [17]

Answer:

4x

Step-by-step explanation:


4 0
3 years ago
(a)<br> Solve.<br> 3x – 4 = x + 5
exis [7]

Answer:

x = 1/2 or 0.5

Step-by-step explanation:

3x - 4 = x +5      (1) subtract x

2x - 4 = 5        (2) subtract 5

2x + 1              (3) divide by 2

x = 1/2 or 0.5

4 0
3 years ago
What is the tan invers of 3i/-1-i​
postnew [5]

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

6 0
3 years ago
Based on the equation 6x + 2y = 30, what is the missing value in the table?
umka2103 [35]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
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35% of what number is 84 ?
satela [25.4K]

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29.4

Step-by-step explanation:

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4 years ago
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