What is the decimal expansion of the following fraction 1/25

Identify the errors the student made

uranmaximum [27]

Answer:

Second step: 2/2 does not give you 2.

It would be 2x + 1 - 4 = 3x - 3

Since he mess up on the second step, the following steps are also messed up

3 0

2 years ago

Current rules for telephone area codes allow the use of digits 2-9 for the first digit, and 0-9 for the second and third dig

Anna35 [415]

Using the fundamental counting theorem, we have that:

648 different area codes are possible with this rule.
There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

8 options for the first digit.
9 options for the second and third.

Thus:

$8 \times 9 \times 9 = 648$

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

7 digits, each with 10 options.
648 different area codes.

Then

$648 \times 10^7 = 6,480,000,000
$

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0

2 years ago

A professor receives, on average, 24.7 emails from students the day before the midterm exam. To compute the probability of recei

MaRussiya [10]

Answer:

Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is $X \sim Poisson(\lambda=24.7)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

The best answer for this case would be:

C. Poisson distribution

Step-by-step explanation:

Let X the random variable that represent the number of emails from students the day before the midterm exam. For this case the best distribution for the random variable X is $X \sim Poisson(\lambda=24.7)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$