Question

The table below gives the distribution of milk

Answer 1

Answer:

0.16

Step-by-step explanation:

Step 1:

Data obtained from the question. This include:

Probability of brown, P(Br) = 0.13

Probability of red, P(R) = 0.13

Probability of yellow, P(Y) = 0.14

Probability of green, P(G) =..?

Probability of orange, P(O) = 0.2

Probability of blue, P(B) = 0.24

Step 2:

Determination of the probability of green candy

Space = {brown, red, yellow, green, orange, blue}

Probability of sampl space, P(S) = 1

P(S) = P(Br) + P(R) + P(Y) + P(G) + P(O) + P(B)

1 = 0.13 + 0.13 + 0.14 + P(G) + 0.2 + 0.24

1 = 0.84 + P(G)

Collect like terms

P(G) = 1 – 0.84

P(G) = 0.16

Therefore, the probability of green candy is 0.16