Answer:
0.16
Step-by-step explanation:
Step 1:
Data obtained from the question. This include:
Probability of brown, P(Br) = 0.13
Probability of red, P(R) = 0.13
Probability of yellow, P(Y) = 0.14
Probability of green, P(G) =..?
Probability of orange, P(O) = 0.2
Probability of blue, P(B) = 0.24
Step 2:
Determination of the probability of green candy
Space = {brown, red, yellow, green, orange, blue}
Probability of sampl space, P(S) = 1
P(S) = P(Br) + P(R) + P(Y) + P(G) + P(O) + P(B)
1 = 0.13 + 0.13 + 0.14 + P(G) + 0.2 + 0.24
1 = 0.84 + P(G)
Collect like terms
P(G) = 1 – 0.84
P(G) = 0.16
Therefore, the probability of green candy is 0.16
