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3 years ago

12

How to represent fracctions on a line

1 answer:

krek1111 [17]3 years ago

6 0

You know the lines on a number line those can be fractions

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Which of the following characteristics of the set {(0 , 8), (8 , 0), (1 , 6), (6 , 1), (2 , 4), (4 , 2)} make it a function?

photoshop1234 [79]

Answer:

C

Step-by-step explanation:

For a relation to be a function, the ordered pairs do not repeat any of the x values. This is Answer C.

6 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Scott bought a 5lb bag of cookies at the bakery. He ate 2/5 of the bag and his sister ate 2/9 of the bag. What fraction of the b

satela [25.4K]

Answer: Fraction they both eat = $\dfrac{28}{45}$ .

Fraction of bag remains = $\dfrac{17}{45}$

Step-by-step explanation:

Given: Part of cookies eaten by Scott = $\dfrac25$

Part of cookies eaten by sister = $\dfrac{2}{9}$

Fraction they both eat = $\dfrac25+\dfrac29=\dfrac{9\times2+5\times2}{5\times9}$

$=\dfrac{18+10}{45}\\\\=\dfrac{28}{45}$

Fraction of the bag remain = $1-\dfrac{28}{45}=\dfrac{45-28}{45}=\dfrac{17}{45}$

[Taking fraction of whole bag =1]

Hence, Fraction they both eat = $\dfrac{28}{45}$ .

Fraction of bag remains = $\dfrac{17}{45}$

4 0

3 years ago

(b) For a function h(theta)=sin3 theta (Theta is in Radian). <br> Find h(pi/3)<br> Find h(pi/2)

vaieri [72.5K]

Part (i)

Plug in theta = pi/3 to get

h(theta) = sin(3theta)

h(pi/3) = sin(3*pi/3)

h(pi/3) = sin(pi)

h(pi/3) = 0 ... use a calculator or the unit circle

<h3>Answer: 0</h3>

=================================================

Part (ii)

Plug in h = pi/2

h(theta) = sin(3theta)

h(pi/2) = sin(3pi/2)

h(pi/2) = -1

<h3>Answer: -1</h3>

5 0

3 years ago

10. If pointer 1 is spun and then pointer 2 is spun, determine the probability of landing on a color other than red on both spin

Brilliant_brown [7]

Answer:

Answer below

Step-by-step explanation:

1/8 is correct

in pic

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(Hope this helps can I pls have brainlist (crown)☺️)

5 0

2 years ago