Answer:
The yield is 5.974%
Step-by-step explanation:
We proceed as follows ;
coupon rate = Annual coupon payment/bond face value.
The face value is the original amount which the bond was bought and that is $515 according to the question. While the coupon rate is 5.8%
mathematically, annual coupon payment = coupon rate * bond face value = 0.058 * 515 = $29.87
mathematically;
current yield = Annual coupon payment/bond price
current yield = 29.87/500
= 0.05974 or simply 5.974%
so the answer is c. 5.6%
Step-by-step explanation:
Let t = time
Between Rocky and Ken:
3000 + 3000(.10)(t)
Between Ken and Mike:
3000 + 3000(.12)(t)
Kens gain = The difference
Cross sections of the volume are washers or annuli with outer radii <em>x(y)</em> + 1, where
<em>y</em> = <em>x(y) </em>² - 1 ==> <em>x(y)</em> = √(<em>y</em> + 1)
and inner radii 1. The distance between the outermost edge of each shell to the axis of revolution is then 1 + √(<em>y</em> + 1), and the distance between the innermost edge of <em>R</em> on the <em>y</em>-axis to the axis of revolution is 1.
For each value of <em>y</em> in the interval [-1, 3], the corresponding cross section has an area of
<em>π</em> (1 + √(<em>y</em> + 1))² - <em>π</em> (1)² = <em>π</em> (2√(<em>y</em> + 1) + <em>y</em> + 1)
Then the volume of the solid is the integral of this area over [-1, 3]:


x = # of ham sandwiches
14-x = # of turkey sandwiches ( as Lexi made 14 sandwiches)
as the question said that the number of ha sandwiches are 4 less than twice number of turkey sandwiches,
x = 2 * (14-x) - 4 = 24 - 2x
3x=24
x = 8
the number of ham sandwiches is 8, and the number of turkey sandwiches is 14-8=6
Answer:
a) 0.19
b) 0.9689
c) ≈ 6 cars
Step-by-step explanation:
Rate at which cars arrive = 12 cars/hour = 1/5 cars/minute
time needed by each car to complete ATM transaction = 6 minutes = 1/6 car/minute
capacity of lane = 10 car
n = 10
<u>a) Calculate the probability of an arriving not using the ATM because the line is full</u>
p ( not using the ATM ) = 0.19
<u>b) probability that a car will not be able to use the ATM machine immediately on arrival</u>
P ( n > 0 ) = 1 - Po
= 1 - 0.0311 = 0.9689
<u>c) Average number of cars in the lane </u>
Lq = 5.74 ≈ 6 cars
attached below is the detailed solution