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PIT_PIT [208]
3 years ago
15

You have two ways to drive home from school: Route A is usually quicker; Route B is

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

0.12 = 12%

Step-by-step explanation:

To find this probability, we need to multiply the probability of getting route B, and the probability of getting home by 4 P.M if we choose route B.

If the probability of choosing route A is 60%, we have that the probability of choosing route B is 100% - 60% = 40%

Then, we have that the probability of getting home by 4 P.M. when choosing route B is 30%, so the final probability is:

P = 40% * 30% = 0.4 * 0.3 = 0.12 = 12%

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Which of the following random variables should be considered continuous? Select one: a. The number of cars owned by a randomly c
kolbaska11 [484]

The Random Variable that should be considered continuous is "The time it takes for a randomly chosen athlete to run 200 meters" , the correct option is (c) .

In the question ,

four random variables are given , we have to select the random variable that is continuous .

A Continuous Random Variable is a random variable X , which can take any value in its domain or in an interval or the union of intervals on the real line is called Continuous random variable .

For Example : weight of middle aged people lying between 40 Kg and 150 Kg .

From the given options ,

the option (c) , the time taken for a randomly chosen athlete to run 200 meters is a interval of time ,

So ,it is can be called as Continuous Random Variable .

Therefore , the option that represents Continuous Random Variable is option(c) .

The given question is incomplete , the complete question is

Which of the following random variables should be considered continuous ? Select one:

(a) The number of cars owned by a randomly chosen adult male

(b) The number of orders received by a mail-order company in a randomly chosen week

(c) The time it takes for a randomly chosen athlete to run 200 meters  

(d) The numbers of brothers a randomly chosen person has .

Learn more about Continuous Random Variable here

brainly.com/question/17238189

#SPJ4

3 0
1 year ago
I need help with three math (algebra) problems?
Bumek [7]
1.
A. (49-8)*2-16, 41*2-16, 82-16, 66, yep
B. 49-8*-14, 49+112, 161, nope
C. 7^(-16)-16, (1/(7^16))-16, nope
D. 49-16-16, 17, nope

A is answer


2.
2((a+b)²-b)
2((7+1)²-1)
2((8)²-1)
2(64-1)
2(63)
126
C is answer


4.
none of the options give the answer
3 0
3 years ago
If a Tv screen is 20in wide and 15in high, what is the length?
yuradex [85]
20:15 which reduces to 4:3 or 4/3 or 4 to 3 , hope that helped have a good day
5 0
3 years ago
Can somebody help me with this?
Juli2301 [7.4K]

Answer:

E) 1/2

Step-by-step explanation:

This is no ordinary problem. It actually requires you to solve two different problems in order to figure out the correct answer.

First, we must figure out what the hypotenuse of the triangle is. We have the two small sides (5 and 12), but don't have the larger side. To find this, we must use the Pythagorean theorem: a^{2} + b^2 =c^2

Let's plug in our a and b values

5^2 + 12^2 = C^2

Simplify

144 + 25 = c^2

169 = c^2

Square both sides

c = 13

But sadly, we aren't done yet. Now we know the length of the whole hypotenuse side. Time to figure out what X is by a simple equation.

12x + 14x = 13

Simplify

26x = 13

Divide by 26

Answer is 1/2

6 0
4 years ago
Your factory produces lemon-scented widgets. You know that each unit is cheaper, the more you produce. But you also know that co
Sindrei [870]

try using m athway . c o m for math help

8 0
3 years ago
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