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PIT_PIT [208]
3 years ago
15

You have two ways to drive home from school: Route A is usually quicker; Route B is

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

0.12 = 12%

Step-by-step explanation:

To find this probability, we need to multiply the probability of getting route B, and the probability of getting home by 4 P.M if we choose route B.

If the probability of choosing route A is 60%, we have that the probability of choosing route B is 100% - 60% = 40%

Then, we have that the probability of getting home by 4 P.M. when choosing route B is 30%, so the final probability is:

P = 40% * 30% = 0.4 * 0.3 = 0.12 = 12%

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kupik [55]
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2 years ago
lucas lives 5/8 mile from school.kenny lives twice as far as lucas from school.how many miles does kenny live from school
dexar [7]
<span><span>1.       </span>Lucas Lives 5/8 miles from their schools
=> 5/8 miles is equals to:
=> 5 / 8 = 0.625 miles.
Now, the problem says that Kenny lives twice as far as Lucas from their school.
Therefore, we only need to multiply the total number of miles of Lucas distance from house to school to be able to get what is the distance of Kenny’s house to school
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3 0
3 years ago
If f(x) = –5x – 4 and g(x) = –3x – 2, find (f – g)(x).
erica [24]

Answer:

  C.  (f – g)(x) = –2x – 2

Step-by-step explanation:

(f – g)(x) = f(x) – g(x)

  = (–5x – 4) – (–3x – 2)

  = –2x – 2

3 0
3 years ago
Help Please!? Thank You!
swat32
A. left 2 units

the vertex form of a parabola is
y = a(x-h)^2 + k
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3 0
2 years ago
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
2 years ago
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