Answer:
The theorem here is essentially that
if a and 3 are disjoint sets with
exactly one element each, then their
union has exactly two elements. ...
Peano shows that it's not hard to
produce a useful set of axioms that
can prove 1+1=2 much more easily
than Whitehead and Russell do.
X = first venture, y = second venture, z = third venture
x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....
x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000
x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000
2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000
x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000
first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
B because it is between x: 4 and 6. And it is linear and decreasing
Answer 2 is 12
Step-by-step explanation:
more than 11 is 12
(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
t^3-t^2-2t+t^2-t-2
t^3+-3t-2
