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gregori [183]
3 years ago
11

Write A Function Rule for the Table

Mathematics
2 answers:
Andrews [41]3 years ago
7 0
It’s B

Because that’s the order that they go in
ohaa [14]3 years ago
6 0

Answer:

B.

Step-by-step explanation:

If you plug in the 1,2,3,4,5 into the x's on the different functions of it = what the f(x) is than that is you answer

You might be interested in
Trapezoids and kites
lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is 360\degree.

\Rightarrow 36\degree +70\degree+m.

\Rightarrow 106\degree+m.

\Rightarrow m.

\Rightarrow m.

But the two remaining opposite angles of the kite are congruent.

\Rightarrow m

\Rightarrow m.

\Rightarrow 2m.

\Rightarrow m.

\Rightarrow m.

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

|RH|^2=12^2+20^2

|RH|^2=144+400

|RH|^2=544

|RH|=\sqrt{544}

|RH|=4\sqrt{34}

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore m

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

m

\Rightarrow m

\Rightarrow m

QUESTION 7

The sum of the interior angles of a kite is 360\degree.

\Rightarrow 48\degree +110\degree+m.

\Rightarrow 158\degree+m.

\Rightarrow m.

\Rightarrow m.

But the two remaining opposite angles are congruent.

\Rightarrow m

\Rightarrow m.

\Rightarrow 2m.

\Rightarrow m.

\Rightarrow m.

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

|BC|^2=4^2+7^2

\Rightarrow |BC|^2=16+49

\Rightarrow |BC|^2=65

\Rightarrow |BC|=\sqrt{65}

QUESTION 9.

The sum of the interior angles of a trapezium is 360\degree.

\Rightarrow m.

\Rightarrow m.

But the measure of angle M and K are congruent.

\Rightarrow m.

\Rightarrow m.

\Rightarrow m.

\Rightarrow m.

6 0
3 years ago
What two integers is 87 between
Alexxx [7]
the two integers 87 between is 86 87 89
7 0
3 years ago
1 BRAINLIEST and 10 points!
erastovalidia [21]

Answer:

≈40.25 Feet

Step-by-step explanation:

The diagnal length of the orchard is the hypotenuse of the triangal with side lengths of 36 and 18.

Therefore, to calculate that, set the hypotenuse as x.

36²+18²=x²

√1620≈ 40.25yards

If I'm wrong I'm so sorry!  I'm wrong sorry

If I'm right Thank you

(lost)

3 0
3 years ago
Read 2 more answers
Please help!!!!!! 50 points!!
lesantik [10]

Area of first rectangle= 5×2=10units

Area of second rectangle= 3×2= 6 units

Area of third rectangle = 5×2= 10 units

Now,

Total area of figure = 10+6+10= <u>26units✓</u>

8 0
3 years ago
Read 2 more answers
Plz help me with this math and also explain
jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

  • SI = $250
  • Rate (R) = 12\sf \dfrac{1}{2} %
  • Time (t) = 4 years

\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\

\longrightarrow \tt { 250 \times 100 = P \times 50} \\

\longrightarrow \tt { 25000 = P \times 50} \\

\longrightarrow \tt { \dfrac{25000}{50} = P } \\

\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

  • 2/7 of the balls are red.
  • 3/5 of the balls are blue.
  • Rest are yellow.
  • Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\

\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\

\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\

\longrightarrow \tt{ 31x + 1260= 35x} \\

\longrightarrow \tt{ 1260= 35x-31x} \\

\longrightarrow \tt{ 1260= 4x} \\

\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\

\longrightarrow \underline{\boxed{  \tt { 315 = x }}} \\

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\

\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\

\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\

8 0
3 years ago
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