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olga55 [171]
3 years ago
11

Help please i don’t understand and this is do today :/!!

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0
The answer is 6.4
This is why

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The vertex of the graph of y = (x - 1)2 - 5 is
Darina [25.2K]

Answer:

(1, -5)

Step-by-step explanation:

7 0
3 years ago
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Linda Barnes has learned from prior studies that one out of five applicants gets admitted to top MBA programs in the country. Sh
LenKa [72]

Answer: 126

Step-by-step explanation:

As per given , we have

Prior Population proportion : p=\dfrac{1}{5}=0.2

Significance level : \alpha=1-0.95=0.05

Critical value for 95% confidence interval (using the z-value table) = z_{\alpha/2}=1.96

Margin of error (maximum error): E=7\%=0.07

Formula to find the sample size :

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\ n=0.20(1-0.20)(\dfrac{1.96}{0.07})^2\\\\ n=125.44\approx126

Therefore , the required minimum sample size = 126

5 0
3 years ago
1. Find the vertices and locate the foci for the hyperbola whose equation is given.
Irina18 [472]
\bf \cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})\\\\
-----------------------------\\\\
\textit{now let's take a look at yours}
\\\\\\
49x2 - 16y2 = 784\implies \cfrac{49x^2}{784}-\cfrac{16y^2}{784}=1
\\\\\\
\cfrac{x^2}{16}-\cfrac{y^2}{49}=1\implies \cfrac{(x-0)^2}{4^2}-\cfrac{(y-0)^2}{7^2}=1
\\\\\\
recall\implies center\ ({{ h}},{{ k}})\qquad vertices\ ({{ h}}\pm a, {{ k}})
\\\\\\


\bf \textit{now, for the foci, the foci are "c" distance from the center point}\\\\\
whereas\qquad c=\sqrt{a^2+b^2}\qquad \textit{ that is }\qquad  h\pm \sqrt{a^2+b^2}

notice your "a" and "b" components, to get the distance "c" from the center to either foci and the vertices, of course, are h + a, k and h - a, k
5 0
3 years ago
Simplify the expression 7.8n²+0.5+9n-.0.4-7n+n²​
Natali [406]

The final answer for this question would be.....

8.8n^2+16n+0.1

Hope this helps!!!!

4 0
3 years ago
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Write the equation of the line that passes through the points (7, -4) and (-1,3), first in point-slope form, and then in
RoseWind [281]

Step-by-step explanation:

first we need to calculate the slope, which is needed in both equation forms.

the slope is the ratio "y coordinate change / x coordinate change" when going from one point on the line to another.

I always prefer to go from left to right (but it works exactly the same way in the opposite direction), so I go from (-1, 3) to (7, -4).

x changes by +8 (from -1 to +7).

y changes by -7 (from +3 to -4).

so, the slope is -7/+8 = -7/8

when (7, -4) is used (I think you have a typo in the problem description up there), the point-slope form is

y - y1 = m(x - x1)

with (x1, y1) being the point coordinates, and m bring the slope

y - -4 = -7/8 × (x - 7)

or simplified

y + 4 = -7/8(x - 7)

the slope-intercept form is

y = mx + n

m being the slope, n being the y-intercept (y value for x=0).

we know already

y = -7/8 x + n

we also use the coordinates of a point here to solve for n :

-4 = -7/8 × 7 + n = -49/8 + n

-32/8 = -49/8 + n

17/8 = n

so, the full equation is

y = -7/8 x + 17/8

5 0
2 years ago
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