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3 years ago

Help please, Lol. TvT

Mathematics

1 answer:

zysi [14]3 years ago

3 0

Answer:

-513.22

Step-by-step explanation:

I don't think they earned any profit. but instead lost money. Sorry it was wrong at first, I misread something.

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The temperature at a mountain base camp was −3 degrees Celsius on Monday. Tuesday morning, the temperature was 2 degrees Celsius

nexus9112 [7]

Answer:

-9 degrees Celsius

Step-by-step explanation:

mark brainliest if helped :)

5 0

2 years ago

Read 2 more answers

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

7 0

3 years ago

Pls help me with this

3241004551 [841]

Answer: D 1 and 5/72 sq ft

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3 years ago

The graph of a function with a y-intercept of -4 and a rate of change of 10

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Using y=Mx+b, the answer is y=10x-4.

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3 years ago

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Its A. duz nuts ah goting

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2 years ago