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svetoff [14.1K]

3 years ago

7

Will give brainliest! On a piece of paper, use a protractor and a ruler to construct △ABC with AB=6 cm , m∠A=90° , and m∠B=45° .

What is AC ?
A:6 cm
B:8 cm
C:9 cm
D:12 cm

2 answers:

vodomira [7]3 years ago

8 0

Since AB is 6cm, and you are working with a right triangle, AC is also 6cm, so your answer is A: 6cm

notka56 [123]3 years ago

3 0

Lukekrista is correct, the answer is A (6cm.)

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When 5x2+2=4x is solved using the quadratic formula, what are the values of a,b, and c?

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Hey there,

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s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

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Part 11) $SF=0.5, x=3.5\ ft$

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Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

3 years ago