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Serggg [28]
3 years ago
8

An easier question all wrong or unhelpful or no-work answers will be reported.

Mathematics
1 answer:
ipn [44]3 years ago
4 0
Elimination: 

3x - 9y = 3
6x - 3y = -24

3x - 9y = 3
18x - 9y = -72
(subtract)
-15x = 75
÷ -15
x = -5

(3 × -5) - 9y = 3
-15 - 9y = 3
+ 15
-9y = 18
÷ -9
y = -2

Substitution:

6x - 3y = -24
+ 3y
6x = -24 + 3y

÷ 6
x = 4 + 0.5y

3(4 + 0.5y) - 9y = 3
12 + 1.5y - 9y = 3
12 - 7.5y = 3
- 12
-7.5y = -9
÷ -7.5
y = 1.2

x = 4 + (0.5 × 1.2)
x = 4 + 0.6
x = 4.6

So this one didn't fail as much, but I got different numbers. If you have to give in values, I'd give in the values from the elimination because I don't trust myself when it comes to the substitution
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Hunter-Best [27]

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Step-by-step explanation:

<u>Part A:</u>

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Determine whether the given set, together with the specified operations of addition and scalar multiplication, is a vector space
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Answer:

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  • The 10th axiom  cv \in V does not hold

Step-by-step explanation:

Let u, v and w be vectors in the vector space V, and let c and d be scalars. A set S is defined as a vector space if it satisfies the following conditions:

  • 1. u+v  \in V
  • 2. v + w = w + v
  • 3. (u + v) + w = u + (v + w)
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If the scalar c is such that c0.

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