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4 years ago

Solve 1.2(5-x) = 2(1.4x+3)

Mathematics

1 answer:

Arturiano [62]4 years ago

4 0

Answer:

x = 0

Step-by-step explanation:

Solve for x:

1.2 (5 - x) = 2 (1.4 x + 3)

Expand out terms of the left hand side:

6 - 1.2 x = 2 (1.4 x + 3)

Expand out terms of the right hand side:

6 - 1.2 x = 2.8 x + 6

Subtract 2.8 x from both sides:

6 + (-1.2 x - 2.8 x) = (2.8 x - 2.8 x) + 6

-1.2 x - 2.8 x = -4 x:

-4 x + 6 = (2.8 x - 2.8 x) + 6

2.8 x - 2.8 x = 0:

6 - 4 x = 6

Subtract 6 from both sides:

(6 - 6) - 4 x = 6 - 6

6 - 6 = 0:

-4 x = 6 - 6

6 - 6 = 0:

-4 x = 0

Divide both sides of -4 x = 0 by -4:

(-4 x)/(-4) = 0/(-4)

(-4)/(-4) = 1:

x = 0/(-4)

0/(-4) = 0:

Answer: x = 0

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3 years ago

PLEASE ANSWER ASAP!!! SHOW ALL THE STEPS.

fenix001 [56]

Answer:

For the first question $x = 4\\ y = -1$ and

For the second question $x = 0.5\\ y = -1$

Step-by-step explanation:

Given:

x - 3y = 7

3x + 3y = 9

8x+ 3y = 1

4x + 2y = 0

Elimination method :

In the elimination method we need to make the coefficient of x or the coefficient of y same in both the equation so by adding or subtracting we can eliminate the x term or the y term.

Then substitute that values which you will get on eliminating in any equation you will get the corresponding value.

For the first question, the y coefficient is same hence by adding both the equation we can eliminate 3y term. so on solving we get

$(x - 3y) + (3x + 3y) = 7 + 9\\4x = 16\\x = \frac{16}{4}\\x = 4$

Now substitute X equal to 4 in equation x -3y = 7 we get

$4 - 3y = 7\\-3y = 7 - 4\\-3y = 3\\y = \frac{3}{-3}\\ y = -1\\$

This way we have x is equal to 4 and y is equal to -1 for question number 1.

For the second question, we will make X coefficient same in the second equation that is multiplying by 2 to the equation 4x + 2y = 0 then we get

$8x + 4y = 0\\$

Now the coefficient of x term become same now we will subtract the two equations that is 8x + 3y = 1 and 8x + 4y =0 we get

$(8x + 3y) - (8x + 4y) = 1 - 0\\3y - 4y = 1\\ -y = 1\\y = -1$

Now substitute y equal to -1 in equation 8x +3y = 1 we get

$8x + 3\times -1 = 1\\8x - 3 = 1\\8x = 1 + 3\\8x = 4\\x = \frac{4}{8}\\ x = 0.5\\$

This way we have x is equal to 0.5 and y is equal to -1 for question number 2.

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