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3 years ago

I’m so confused! Please help! :)

Mathematics

1 answer:

s2008m [1.1K]3 years ago

8 0

Answer:

The answer is 18.84

Step-by-step explanation:

The diameter is 6.

Circumference = d $\pi$

6 * 3.14 = 18.84

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Salsk061 [2.6K]

Answer:

a = 8 ÷ 1/8

Step-by-step explanation:

All I really did was put another variable similar to the x in the original problem, then I changed the numbers to be a bit lower while still keep the original work-- In a short term, I lowered the 9s to 8s.

4 0

3 years ago

Which of the following is used to inscribe a square in a circle?

katrin [286]

Answer:

The option which is used to inscribe a square in a circle is option B

B. Construct a perpendicular bisector of the diameter of the circle

Step-by-step explanation:

The steps required to inscribe a square in a circle are;

1) Draw the circle using a compass

2) Draw the diameter of the circle, that passes through the center of the circle with a straight edge label the endpoint of the diameter X and Y

3) Construct the line perpendicular to the diameter of the circle and label the endpoints as A and B

The figure formed by joining the endpoints X, Y, A, and B is the inscribed square of the circle

Therefore, the correct option is to construct a perpendicular bisector of the diameter of the circle.

8 0

3 years ago

Solve Y+3/5 = 1 1/10

lesya [120]

Answer:

y = 1/2

Step-by-step explanation:

Y+3/5 = 1 1/10

Subtract 3/5 from both sides.

y = 1/2

3 0

2 years ago

Factor x^2+6x-16 into the form (x+a)(x-b), what is a and b?

vfiekz [6]

Answer:

a=-8 b=2

Step-by-step explanation:

x^2+6x-16

x^2+(8-2)x-16=0

x^2+8x-2x-16=0

X(X+8)-2(X+8)=0

(X+8)(x-2)=0

Compare with (X+a)(X+b)

Where we get a=-8 b=2

8 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago