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3 years ago

13

At a sale, coats were sold for $10 each. If the coats originally cost $20 each, what percentage of its original price was a coat

sold for?

2 answers:

Anvisha [2.4K]3 years ago

6 0

Answer: 50%

Step-by-step explanation:

10/20×100=50%

IRISSAK [1]3 years ago

5 0

Answer:

50

Step-by-step explanation:

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Use the method that you described in item 4 to answer the following

Kruka [31]

Answer:

Step-by-step explanation:

3 0

3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago

A. What is the monthly payment for a<br>$3,200 five-year loan with an APR of 3%.

madreJ [45]

Answer:

$57.50

Step-by-step explanation:

we know that

The monthly loan payment formula is equal to

$M=\frac{P(\frac{r}{12})(1+\frac{r}{12})^{12t}}{(1+\frac{r}{12})^{12t}-1}$

where

M ----> is the monthly payment

P ---> the amount borrowed

r ---> interest rate as decimal

t ---> length of the loan in years

we have

$t=5\ years\\ P=\$3,200\\ r=3\%=3/100=0.03$

substitute in the formula

$M=\frac{3,200(\frac{0.03}{12})(1+\frac{0.03}{12})^{12(5)}}{(1+\frac{0.03}{12})^{12(5)}-1}$

$M=\frac{3,200(0.0025)(1.0025)^{60}}{(1.0025)^{60}-1}$

$M=\$57.50$

4 0

3 years ago

qwelly [4]

Page 142 #4 round your answer the nearest

5 0

3 years ago

last year Mrs del Greco spend $572 on gas. this year because she did not drive as much she spent $393 what is the percent change

rosijanka [135]

Answer:

68%

Step-by-step explanation:

Divide the amount she spent this year, by the amount she spent last year, in this case, 393 divided by 572 =0.68706293706, but we need to make it into hundredths, so it is 0.68, or 68%.

5 0

3 years ago