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Anuta_ua [19.1K]
2 years ago
13

Jose and juan went running. jose ran 2 miles less than 1/2 as many miles as juan. jose ran 6 miles. how many miles did juan run?

Mathematics
2 answers:
geniusboy [140]2 years ago
8 0
It says that Jose ran 2 miles less than half of the miles Juan ran. Add 2 miles to the number of miles Jose ran:
6 + 2 = 8.
8 miles is half of what Juan ran so you need to multiply 8 by 2:
8*2 = 16. 

This can be expressed as an equation like this:
Juan = 2*(Jose+2)
ollegr [7]2 years ago
4 0
If jose is 2 miles less than half of juan then the answer should be like 2. because 6 minus 2 is 4 and 4 divided by 2 is 2

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3 years ago
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Find the Length of AC. Round answers to the nearest hundredth (2 decimal places)
lara31 [8.8K]

Answer:

32.78

Step-by-step explanation:

Assuming that we have two right triangles joined together, with one having adjacent side a, with a side of 12 ft opposite reference angle 30°, and the other one having adjacent side b, with a side of 12 ft opposite reference angle 45°. Thus, a + b = length of AC.

Let's find a and b.

Finding a:

Reference angle = 30°

Opp = 12 ft

Adj = a

Using trigonometric ratio formula, we have:

tan(30) = 12/a

Multiply both sides by a

a*tan(30) = 12

Divide both sides by tan(30)

a = 12/tan(30)

a = 20.78 (nearest hundredth)

Finding b:

Reference angle = 45°

Opp = 12 ft

Adj = b

Using trigonometric ratio formula, we have:

tan(45) = 12/b

Multiply both sides by a

b*tan(45) = 12

Divide both sides by tan(45)

b = 12/tan(45)

a = 12

Length of AC = 20.78 + 12 = 32.78

5 0
3 years ago
Which of these ratios is not a rate?
Doss [256]

Answer:

i think it is B

Step-by-step explanation:

because that one isn't really a rate as much as the other ones are, its more of a ratio, i'm bad at explaining things, hope its correct :D

6 0
3 years ago
Find the length of a side of an equilateral triangle given its altitude is six inches long.
vampirchik [111]
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The altitude divides it into two 30 60 90 triangles.
The altitude is the "middle side" of such a triangle.
When that is the case, the middle side divided by the square root of 3 = the short side and multiplied by (2/sq root (3)) equals the hypotenuse.
The hypotenuse is the side of the equilateral triangle. 
So, 6 * 2 / (sq root of 3) = <span> <span> <span> 6.9282032303 </span> </span> </span>

Source:
http://www.1728.org/trig2.htm


8 0
3 years ago
Which of the following equations represents the perpendicular bisector of WX graphed below?
kotykmax [81]
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2} )=  (\frac{-5+5}{2},  \frac{2+(-4)}{2} )=(0, -1).

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is \displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}.

Thus, the slope n of the perpendicular line is \displaystyle{  \frac{5}{3}.

The equation of the line with slope \displaystyle{ n= \frac{5}{3} containing the point M(0, -1) is given by:

\displaystyle{ y-(-1)=\frac{5}{3}(x-0)

\displaystyle{ y+1= \frac{5}{3}x

\displaystyle{ 3y+3=5x

\displaystyle{ 5x-3y-3=0

Answer: 5x-3y-3=0
8 0
3 years ago
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