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lara [203]
3 years ago
8

Write a paragraph explaining what scattered plots are and how to solve them. Make sure to give details, key terms and an example

on how to solve scattered plots.
Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

x = 59°

y = 67°

Step-by-step explanation:

x = y - 8

x + y + 54 = 180

(y - 8) + y = 180 - 54

2y - 8 = 126

2y = 134

y = 67°

x = 59°

Step-by-step explanation:

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(1-(-3)/9-(-3)) solve
podryga [215]

Answer:

4.33333333333

Step-by-step explanation:

4 0
3 years ago
Graph each of the equations and then determine which one represents the rank catcher that is elevated
Tanya [424]
We have two functions that are Parabolas. A parabola is a type of quadratic function which is a special type of “U”-shaped curve called. So let's solve this problem for the first parabola and then for the second one.

1. Graph of the first equation

We have that:

y=x^2-2x+3

So if we graph this equation, the parabola that matches it is shown in Figure 1.

1.1 Direction of Parabola

In general, a parabola or quadratic function is given by the following way:

y=ax^2+bx+c \\ \\ where \ "a" \ is \ called \ the \ leading \ coefficient

Given that our leading coefficient is positive, then the direction of the parabola is upward, that is, it opens upward.

1.2 Location of vertex with respect to the x-axis

The vertex a parabola can be found as follows:

(-\frac{b}{2a},f(-\frac{b}{2a}))

But: \\ \\ a=1 \\ b=-2 \\ c=3 \\ \\ Accordingly: \\ \\ -\frac{b}{2a}=-\frac{(-2)}{2(1)}=1 \\ \\ f(1)=1^2-2(1)+3=2 \\ \\ So \ the \ vertex \ is: \\ \\ V(1,2)

So the vertex is located two units above the x-axis.

<span>1.3 Determine if the graph depicts the rain gauge
</span>
A rain gauge is an instrument used by meteorologists and hydrologists to gather and measure the amount of liquid precipitation<span> over a set period of time.
</span>
From Figure 4 we can affirm that this is the parabola that resembles a rain gauge elevated from the ground. 

1.4 Why or why not?

It basically the question asks for the parabola that has a vertex well above the x-axis. From Figure 4, you can see that the elevated parabola is in fact:

y=x^2-2x+3

2. Graph of the second equation

We have that:

y=x^2+4x+4

So if we graph this equation, the parabola that matches it is shown in Figure 2.

2.1 Direction of Parabola

As in the previous problem, given that our leading coefficient is positive, then the direction of the parabola is also upward, that is, it opens upward.

2.2 Location of vertex with respect to the x-axis

The vertex of a parabola can be found as follows:

(-\frac{b}{2a},f(-\frac{b}{2a}))

In \ this \ case: \\ \\ a=1 \\ b=4 \\ c=3 \\ \\ Accordingly: \\ \\ -\frac{b}{2a}=-\frac{4}{2(1)}=-2 \\ \\ f(-2)=(-2)^2+4(-2)+4=0 \\ \\ So \ the \ vertex \ is: \\ \\ V(-2,0)

So the vertex lies on the x-axis.

2.3 Determine if the graph depicts the rain gauge

This parabola does not resembles a rain gauge elevated from the ground.

2.4 Why or why not?

As you can see the parabola touches the x-axis. If the x-axis represents the ground, then the rain gauge is touching it, that is, it is not elevated.

3. Graph of the third equation

We have that:

y=3x^2+21x+30

So if we graph this equation, the parabola that matches it is shown in Figure 5.

3.1 Direction of Parabola

As in the previous parabolas, given that our leading coefficient is positive, then the direction of the parabola is also upward, that is, it opens upward.

3.2 Location of vertex with respect to the x-axis

In \ this \ case: \\ \\ a=3 \\ b=21 \\ c=30 \\ \\ Accordingly: \\ \\ -\frac{b}{2a}=-\frac{21}{2(3)}=-\frac{7}{2} \\ \\ f(-\frac{7}{2})=3(-\frac{7}{2})^2+21(-\frac{7}{2})+30=-\frac{27}{4} \\ \\ So \ the \ vertex \ is: \\ \\ V(-\frac{7}{2},-\frac{27}{4})

So the vertex is shifted \frac{27}{4} units downward the x-axis.

3.3 Determine if the graph depicts the rain gauge

This parabola does not resembles a rain gauge elevated from the ground.

3.4 Why or why not?

The vertex of this parabola lies on the negative y-axis. So it is not elevated from the ground.

5 0
2 years ago
What’s the area of a square the side is 7x-3
Gnoma [55]

Area of a square = Side × Side

Side = 7x-3

Area of the square = (7x-3) × (7x-3)

= 7x(7x-3) -3(7x-3)

= 49x^2 -21x -21x +9

=49x^2 -42x +9

4 0
2 years ago
Enter the number in sdentific notation. 86,257 = Hint: Move the decimal left 4 places.​
marin [14]

Answer:

8.6257*10^4

Step-by-step explanation:

move the decimal left 4 places

multiply 10^however many decimal places you moved

boom

6 0
3 years ago
An ant population starts at 1200 for a certain colony. As each month goes by in the winter, 6.5% of the population dies off. How
Nitella [24]

Answer:

There will be 916 ants alive after 4 months.

Step-by-step explanation:

Step 1

Let's change the percentage to a decimal by dividing by a 100.

6.5% / 100 = .065

Step 2

So, for the first month we will multiply the initial amount of ants by .065 and this will give us the number of ants that die.

1200 * .065 = 78

This means that after the first month, 1200 - 78 = 1122 ants will be alive.

Step 3

Now for the second month: 1122 * .065 = 72.93 (rounded to 73)

1122 - 73 = 1049 ants will be alive

Step 4

For the third month 1049 * .065 = 68.185 (rounded to 68)

1049 - 68 = 981 ants will be alive

Step 5

For the fourth month 981 * .065 = 63.765 (rounded to 64)

981 - 64 = 916 ants will be alive

Hope this helps!

5 0
2 years ago
Read 2 more answers
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