2 years ago

What’s is radical 256

Mathematics

1 answer:

brilliants [131]2 years ago

6 0

Answer: 16

Radical 256 (square root) = 16 x 16

You might be interested in

13 yd<br>Circumference =.

k0ka [10]

Answer:

yjajsjsuwjjajaiwija

6 0

2 years ago

Please someone right now please 10x23-9+90(23-9)

Burka [1]

Answer:

1481

Step-by-step explanation:

8 0

1 year ago

What is the value of x and y

Anestetic [448]

Step-by-step explanation:

8y+17°=6x+7° (vertical opposite angle)

6x+7=3x-29. (interior angle on same side)

3x=-36

x=-12°

B=C

-72+7=-36-29

-65=-65

6 0

2 years ago

Mrs. Laura is between 50 and 80. If you divide her age by 9, the remainder is 1. If you divide by 4, the remainder is 1. How old

Mila [183]

Answer:

73 y/o

Step-by-step explanation:

Multiples of 9 between 50 and 80:

54 63 72 now add 1

55 64 73 now divide by 4 to find which has remainder of 1

73 y/o

3 0

1 year ago

Read 2 more answers

Please help I am so lost!!!

ASHA 777 [7]

$\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\$

$\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{2[1-cos(x)]}{sin(x)[1-cos(x)]}\implies \cfrac{2}{sin(x)}\implies 2\cdot \cfrac{1}{sin(x)}\implies 2csc(x)$

4 0

2 years ago