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3 years ago

1+1Plz give good reasoning why this is an snwer

1 answer:

6 0

Answer: 1+1 is equal to 2, because adding a singular object to a specified amount of something to the number 1, it will increase by just that. Therefore, if the quantity of something is one, adding the number one to its value will be the number 2.

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Pretty ez ngl but need help extra points

baherus [9]

Answer:

Concept: Algebraic Manipulation

90* 1/6 = 15
Hence its 15 dollars
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5 0

2 years ago

Read 2 more answers

PLS HELP ASAPPP I WILL GIVE BRAINLIEST

FrozenT [24]

Answer:

Yes, it is.

Step-by-step explanation:

6 0

2 years ago

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HELP PLEASE. A pizza shop charges customers based on the area of the pizza they order. The cost of a pizza in dollars can be rep

san4es73 [151]

For this case we have that the cost of each pizza is given by the following function:

$S (r) = 0.1 \pi * r ^ 2$

Where:

r: It's the radius of the pizza

IF a pizza cost $26.32 we have:

$26.32 = 0.1 \pi * r ^ 2$

We cleared the radius, using $\pi = 3.14$ :

$\frac {26.32} {0.1} = \pi * r ^ 2\\263.2 = 3.14r ^ 2\\\frac {263.2} {3.14} = r ^ 2\\83.82 = r ^ 2\\r = \pm \sqrt {83.82}$

We choose the positive value:

$r = 9.15$

So, the radius of the pizza is $9.16 \ in$

Then, the diameter is: $2r = 2 * 9.15 = 18.30 \ in$

Finally, the diameter of the pizza is: $18.30 \ in$

Answer:

Option B

4 0

3 years ago

Read 2 more answers

The random variable X is normally distributed. P(2045).

bekas [8.4K]

What the answer option

4 0

2 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago