1/2
plsss mark brainliestt
Step-by-step explanation:
3/6
1.5/3
5/2.5
Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
Answer:
x = -5/31
Step-by-step explanation:
5(5x + 1) = 3x - 9x multiply 5 with the inside of the parenthesis, 5(5x + 1) = 25x + 5
25x + 5 = 3x - 9x add the like terms, 31x = -5 and x = -5/31
