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Alik [6]
3 years ago
14

What is the value of f(-4) in the piecewise function f(x)= -x-5 for -5<= x <= -2; -x^2+1 for -2<=x<=2; (x-3)^2+2 for

2<=x<=4? If that makes any since
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
6 0

Answer:

The value for f(-4) in the piecewise function is -1

Step-by-step explanation:

As the function is defined by pieces we must choose the correct interval when replacing. In this case, the value of the function needs to be calculated in x=4.  

This value of x is within the interval:

-5<=x<=-2

Therefore we replaced in the corresponding expression:

f(x)=-x-5

f(-4)=-(-4)-5=-1

Take into account this case is not particularly a function since, for example, in the value of x=-2 the expression can take two values corresponding to two different pieces.  The obtained result is only valid in the range for -5<=x<=-2.

Alik [6]3 years ago
5 0


We first need to pick the correct piece to use. In this case, we will use f(x) = -x-5 because -5<=-4.

Then, we use direct substitution:
f(-4) = -(-4) - 5
f(-4) = -1

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Paul is taking inventory of unsold ladies’ dresses from last month. The following matrix shows how many of each dress were left
Allisa [31]

Answer:

A

Step-by-step explanation:

Just add both matrices

5 0
3 years ago
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Mr. Hans wants to give an award to the student with the best jump rope rate. Linda can jump rope 120
Gelneren [198K]

Answer:

c)  Mike receives the award for being the best at jumping rope.

Step-by-step explanation:

Here, according to the question

Jumping rate of Linda = 120 times in 4 minute

So, number of jumps Linda does per minute = (120/4) = 30

So, Jumps per minute of Linda is 30.

Jumping rate of Carl  = 315 times in 9 minute

So, number of jumps Carl does per minute = (315/9) = 35

So, Jumps per minute of Carl is 35.

Jumping rate of Mike = 252 times in 7 minute

So, number of jumps Mike does per minute = (252/7) = 36

So, Jumps per minute of Linda is 36.

Now if we compare the <u>jumps per minute</u> of Linda , Carl and Mike, weget that Mike has the best rate of 36 jumps per minute.

Hence, Mike receives the award for being the best at jumping rope.

4 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
Idk why I can’t get this ?! number two plz
Arturiano [62]
The only possible outcome to this would be any number greater or less than 361 in the 300’s
7 0
3 years ago
In the ellipse shown below, the red line segment is called the?
koban [17]

An ellipse uses major axis  and minor axis.

The major is the larger axis and the minor is the smallest.

Since this ellipse is wider than it is tall the horizontal red line would be the major axis.


The answer is B.

7 0
3 years ago
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