Pat needs to paint an 8 ft x 36 ft rectangular wall. what is the area that she paints?

3a+5b-9: a=2, b=3 that is my question I need help

Zigmanuir [339]

Answer:

12

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The table shows transactions from five different bank accounts. Fill in the missing numbers. ( THE IMAGE ATTACHED PLEASE)

velikii [3]

Answer:

Part 1) $A=80$

Part 2) $B=-25$

Part 3) $C=-40$

Step-by-step explanation:

we know that

The old account balance plus the transaction amount is equal to the new account balance

The transaction amount can be a positive number (example a deposit) or a negative number (example a withdrawal)

Part 1) Find the value of A

$432+A=512$

solve for A

subtract 432 both sides

$A=512-432=80$

Part 2) Find the value of B

$75-100=B$

solve for B

$-25=B$

Rewrite

$B=-25$

Part 3) Find the value of C

$C+52=12$

solve for C

subtract 52 both sides

$C=12-52$

$C=-40$

4 0

3 years ago

Find the 8th term of the geometric sequence, given the first term and common ratio. a1=6 r=-1/3

Damm [24]

The rule of a geometric sequence:

$a_n=a_1r^{n-1}$

We have:

$a_1=6;\ r=-\dfrac{1}{3}$

Find $a_8=?\to n=8$

substitute:

$a_8=6\cdot\left(-\dfrac{1}{3}\right)^{8-1}=6\cdot\left(-\dfrac{1}{3}\right)^7=6\cdot\left(-\dfrac{1}{2187}\right)=-\dfrac{2}{729}$

8 0

3 years ago

Can someone please help me

astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2 ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1 now substitute L=n+2

G1(n) = 2(n+2) -1 simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0

3 years ago

A large truck has two fuel tanks, each with a capacity of 150 gallons. Tank 1 is half full, and Tank 2 is empty.

12345 [234]

Answer:

1) $G(t) = 75 + \frac{23}{4}t\\$

2) After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

Step-by-step explanation:

1) For generating the equation we have to take into account that in the tanks there is a initial volume of fuel that corresponds to 75 gallons, as it is stated that tank one is half full. As the capacity for tank 1 is of 150 gallons, half of the tank equals to:

$\frac{150}{2} = 75 gallons$

Now we have to convert the rate of delivery that is expressed as a mixed number to an improper fraction so:

$5\frac{3}{4} = \frac{(5x4)+3}{4} = \frac{23}{4}$

Then the pumping rate is of 23/4 gallons per minute, to get how many gallons are in the tank we just need to multiply this rate by the time in minutes, and as there is an initial volume we have to add it, so we have the following equation:

$G(t) = 75 + \frac{23}{4}t\\$

2) To know how much fuel is in the tank after 8 minutes we have to replace this time in the previous equation so we have

$G(t) = 75 + \frac{23}{4}t\\G(8) = 75 + \frac{23}{4}(8)\\G(8) = 75 + 23(2)\\G(8) = 75 + 46\\G(8) = 121 gallons$

After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

8 0

3 years ago