Answer: 2 lbs of cherries
Cherries = $5 per pound
Oranges = $2 per pound
Total Cost = $18
Total weight = 6 lb
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Define x and y
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Let x be the number of lb of cherries
Let y be the number of lb of oranges
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Construct equations
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x + y = 6 ---------------------------- (1)
5x + 2y = 18 ---------------------------- (2)
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Solve x and y
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From equation (1):
x + y = 6
x = 6 - y
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Substitute x = 6 - y into equation 2
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5x + 2y = 18
5 (6 - y) + 2y = 18
30 - 5y + 2y = 18
3y = 30 - 18
3y = 12
y = 4
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Substitute y = 4 into equation (1)
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x + y = 6
x + 4 = 6
x = 2
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Find the weight of cherries and oranges
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Cherry = x = 2 lb
Oranges = y = 4 lbs
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Answer: Alex bought 2 lb of cherries
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It’s B
If y-x=6
Y +X =_10
then y= 6 + x, instead of y insert this no
6+ x+ x =-10
6 + 2x =-10 then collect like terms
2x =-10-6
2x=-16 then multiple both side by 1/2
X=-8
Y=6+x instead of x insert -8
Y=6-8
=-2
Answer:
P(4≤x≤7) = 2/3
Step-by-step explanation:
We'll begin by obtaining the sample space (S) i.e possible outcome of rolling both dice at the same time. This is illustrated below:
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6
Adding the outcome together, the sample space (S) becomes:
2 3 4 5 6 7
3 4 5 6 7 8
4 5 6 7 8 9
5 6 7 8 9 10
6 7 8 9 10 11
7 8 9 10 11 12
Next, we shall obtain the event of 4≤x≤7. This is illustrated below:
4 5 6 7
4 5 6 7
4 5 6 7
4 5 6 7
4 5 6 7
4 5 6 7
Finally, we shall determine P(4≤x≤7). This can be obtained as follow:
Element in the sample space, n(S) = 36
Element in 4≤x≤7, n(4≤x≤7) = 24
Probability of 4≤x≤7, P(4≤x≤7) = ?
P(4≤x≤7) = n(4≤x≤7) / nS
P(4≤x≤7) = 24/36
P(4≤x≤7) = 2/3
.... Hope this will help....
The first triangle has a perimeter of 4+6+10 = 20.
The 2nd longest side is 6/20 = 3/10 of the perimeter. In the larger triangle, the 2nd longest side will have length (3/10)*60 = 18.
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These side lengths mean the "triangle" is a line segment. That is, it has zero area.
