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2 years ago

Which equation represents a line that passes through (-2,4) and has a slope of 2/5?

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

6 0

Answer:

$\large\boxed{y=\dfrac{2}{5}x+\dfrac{24}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the slope $m=\dfrac{2}{5}$ and the point (-2, 4).

Put them in the equation of a line:

$4=\dfrac{2}{5}(-2)+b$

$4=-\dfrac{4}{5}+b$ <em>add 4/5 to both sides</em>

$4\dfrac{4}{5}=b\to b=\dfrac{24}{5}$

Tatiana [17]2 years ago

5 0

Answer:

I think that the answer is C

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mafiozo [28]

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3 years ago

In the figure is a right triangle ABC with AC=10cm and BC=6cm. Determine: 1.5.1 The height AB (hint: Theorem of Pythagoras)

Alexxandr [17]

Answer:

height AB is 8 cm

Step-by-step explanation:

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3 0

3 years ago

What digit makes each number divisible by nine?<br><br> _7,302

Alborosie

Answer:

Not completely sure but hopefully these will help.

Step-by-step explanation:

I'm kind of confused what you're asking for. If you could clarify that would be great. If you're trying to make it divisible by 9, you can either do 3, 6 or 9. If you want the first two digits: 2,5,8. Please clarify so I can help

8 0

3 years ago

All in standard Notation please :/ 2.09 x 10^5

Assoli18 [71]

9514 1404 393

Answer:

209,000
94,387
0.0013

Step-by-step explanation:

Write the power of ten in standard form and do the multiplication.

2.09 × 10^5 = 2.09 × 100,000 = 209,000

9.4387 × 10^4 = 9.4387 × 10,000 = 94,387

1.3 × 10^-3 = 1.3 × 0.001 = 0.0013

5 0

3 years ago

The height of an object tossed upward with an initial velocity of 120 feet per second is given by the formula h = −16t2 + 120t,

AleksAgata [21]

Answer:

7.5 seconds

Step-by-step explanation:

$h = - 16 {t}^{2} + 120t \\ \because \: we \: have \: to \: find \: the \: time \: required \: \\ for \: the \: object \: to \: return to \: its \: \\ point \: of departure. \\ \therefore \: plug \: h = 0 \: in \: the \: given \: euation. \\ \therefore \: 0 = - 16 {t}^{2} + 120t \\ \therefore \:16 {t}^{2} - 120t = 0 \\ \therefore \:8t(2t - 15) = 0 \\ \therefore \:8t = 0 \: \: or \: \: (2t - 15) = 0 \\ \therefore \:t = \frac{0}{8} \: or \: t = \frac{15}{2} \\ \therefore \:t = 0 \: or \: t = 7.5 \\ \because \: t = 0 \: is \: not \: possible \\ \huge \purple{ \boxed{ \therefore \: t = 7.5 \: seconds}}$

Thus, the time required for the object to return to its point of departure is 7.5 seconds.

4 0

2 years ago