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kykrilka [37]
3 years ago
7

Can someone explain and answer

Mathematics
2 answers:
Gwar [14]3 years ago
7 0
The answer is D. y = -2x + 20. This is because it has a negative slope (-2x). When a number in a slope-intercept equation has the variable (x), that determines the positive or negative association. If it is a positive slope, it travels up from left to right. If it is a negative slope, it travels down from left to right.
nirvana33 [79]3 years ago
7 0

Answer:

D. y = -2x + 20

Step-by-step explanation:

first, plot these points on a linear graph.

work down from the top:

A. y = 2x <u>+ 5</u>

look at the last number first, this means the line will cross over the y axis (vertical line) at + 5. draw a point on + 5

y = <u>2x</u> + 5

From this point (+5), the 2x means that for every 1 square you move across (to the right), you will go up 2. This will make the second point of the line. connect the dots. (see picture 1 below)

B. y = 2x <u>- 6</u>

the last number means the first point will be on -6 on the y axis.

y = <u>2x</u> - 6

the 2x means that every 1 square you go across (to the right) from that point, you will move up 2

C. y = 2x

as there is no second number, this line will cross through the center of the graph. the 2 means that for every 1 square you move across from that point, you will move up 2

D. y = -2x <u>+ 20</u>

the +20 means this line will cross the y axis and + 20, the -2 means that for every 1 square you move across to the right, you move <u>DOWN</u> 2.

this is the only line that moves down from left to right

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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




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3 years ago
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Answer:

4

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The area, a of the room is 8* 5.5

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To get the number of packages needed, simply divide the area of the room by 12

This gives:

44/12 = 4

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Consider the following figure:
motikmotik

Answer:

angle <B = 76

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The measure of an exterior angle is equal to sum of two interior angles that is not adjacent to the exterior angle.

We can write the following equation with this information to find the value of angle <B

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<B = 76

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