solution: Mr. Schwartz will need to order more wheels after building 12 cars.
explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
Answer:
6.8
Step-by-step explanation:
simply subtract the length of RT from RV
13.1 - 6.3
degree
The largest exponent in the polynomial is called the degree, and the coefficient of the variable raised to that exponent is called the leading coefficient. The constant in a polynomial has no variable written next to it.
Answer:
The answer is 11n.
Step-by-step explanation:
This is because 6n and 5n have the common term of n and you can add them up as if it were just 6 + 5.
6n + 5n = 11n
