A. Every month Population will increase by a factor of 0.84%.
B. Every 3 months Population will increase by a factor of 2.5%.
C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.
<u>Step-by-step explanation:</u>
Here, we have number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as 
which is equivalent to 
.
<u>A.</u>
For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like 
. ∴ Every month Population will increase by a factor of 0.84%.
<u>B.</u>
In every 3 months: We have , 12 months in a year , in order to check for every 3 months 
and Now, Population increase in every 3 months is 
. ∴ Every 3 months Population will increase by a factor of 2.5%.
<u>C.</u>
In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.
So , increase in population in every 20 months is 10% + 6.72% = 16.72%.
-2x^2 + 3x - 9 = 0
The quadratic is not factorable so quadratic formula must be used.
x = (-b + - √(b^2 - 4ac))/2a
a = -2, b = 3, c = -9
x = (-3 + - √(9 - 4*-2*-9))/-4
x = (-3 + - √(-63))/-4
x = -3 + - 3i√7
--------------
-4
x = 3 + 3i√7 x = 3 - 3i√7
------------ ------------
4 4
Answer: brand C
Step-by-step explanation:
i just took the quiz
Given:
Sample size, n = 40
Sample mean, xb = $6.88
Population std. deviation, σ = $1.92 (known)
Confidence interval = 90%
Assume normal distribution for the population.
The confidence interval is
(xb + 1.645*(σ/√n), xb - 1.645*(σ/√n)
= (6.88 + (1.645*1.92)/√40, 6.88 - (1.645*1.92)/√40)
= (7.38, 6.38)
Answer: The 90% confidence interval is (7.38, 6.38)
The ranges of batting averages were least common among the players is 0.320-0.329 and 0.360-0.369 , Option D is the correct answer.
<h3>What is meaning of Average ?</h3>
Average is the middle value of a set of data points , calculated by summing all the data points and then dividing by the number of points.
It is given that , 30 best batting averages for a semi-pro baseball league.
The ranges of batting averages were least common among the players
To find this , it has to be observed that which range has the lowest frequency
The range 0.320-0.329 and 0.360-0.369 has frequency of 1 which is the least among all
Hence Option D is the correct answer.
To know more about Average
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