Answer:
All of the above
Explanation:
An interrupt priority scheme is a system which decides the priority at which various work is done and it perform all of the above mention task so therefore all of the above is the right answer.
Answer:
def analyze_text(sentence):
count = 0
e_count = 0
for s in sentence:
s = s.lower()
if s.isalpha():
count += 1
if s == "e":
e_count += 1
return "The text contains " + str(count) + " alphabetic characters, of which " + str(e_count) + " (" + str(e_count*100/count) + "%) are ‘e’."
Explanation:
Create a function called analyze_text takes a string, sentence
Initialize the count and e_count variables as 0
Create a for loop that iterates through the sentence
Inside the loop, convert all letters to lowercase using lower() function. Check each character. If a character is a letter, increment the count by 1. If a character is "e", increment the e_count by 1.
Return the count and e_count in required format
Answer:
c3 and c4 and c2 are different and same
Explanation:
average cells are ptoboxide
I would have to say that the M3(ury would be the MOST effective, because it has more capitals, numbers, and symbols, which would make it harder to hack into.
Answer:D is the answer to this one
