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Lelechka [254]
3 years ago
6

What is a benifit of having a client/server network?

Computers and Technology
1 answer:
podryga [215]3 years ago
4 0
There are advantages and disadvantages to both peer-to-peer and client-server networks; however, in general, small businesses benefit more from a client-server network designed to maximize your employees' productivity through enhanced security, reliability, and accessibility features.
You might be interested in
Explain how a touris could use QR codes at an airport to help plan a holiday
elena55 [62]

Answer:

with tech

Explanation:

8 0
3 years ago
In a block of addresses we know the IP address of one host is Roll no. Roll no. Roll no. Roll no./20.What is the first address a
lesya [120]

Answer:

If there’s one topic that trips people up (both new and experienced) in the networking industry, it is that of Subnetting.

One of the reasons this happens is that one has to perform (mental) calculations in decimal and also binary. Another reason is that many people have not had enough practice with subnetting.

In this article, we will discuss what Subnetting is, why it came about, its usefulness, and how to do subnetting the proper way. To make this article as practical as possible, we will go through many examples.

Note: While subnetting applies to both IPv4 and IPv6, this article will only focus on IPv4. The same concepts explained here can be applied to IPv6. Moreover, subnetting in IPv6 is more of a want rather than a necessity because of the large address space.

IP address network

For example, any traffic with a destination IP address of 192.168.1.101 will be delivered to PC1, while traffic addressed to 192.168.1.250 will be delivered to SERVER.

Note: This is an oversimplification of things just for understanding sake and refers to Unicast (one-to-one) IPv4 addresses. Traffic sent to Multicast (one-to-many) and Broadcast (one-to-all) IP addresses can be delivered to multiple devices. Also, features like Network Address Translation (NAT) allow one IP address to be shared by multiple devices.

To help your understanding of IP addresses and subnetting, you need to resolve the following fact in your head: Computers think in binary, that is, 0s and 1s. Therefore, even though we see an IP address represented like 192.168.1.250, it is actually just a string of bits – 32 bits in total for IPv4 addresses.

To make them more readable for humans, IPv4 addresses are represented in dotted decimal notation where the 32 bits are divided into 4 blocks of 8 bits (also known as an octet), and each block is converted to a decimal number.

For example, 01110100 in binary is 116 in decimal:

A unicast IPv4 address such as 192.168.1.250 can be divided into two parts: Network portion and Host ID. So what does this mean? Well, IPv4 addresses were originally designed based on classes: Class A to Class E. Multicast addresses are assigned from the Class D range while Class E is reserved for experimental use, leaving us with Class A to C:

Class A: Uses the first 8 bits for the Network portion leaving 24 bits for host IDs. The leftmost bit is set to “0”.

Class B: Uses the first 16 bits for the Network portion leaving 16 bits for host IDs. The two leftmost bits are set to “10”.

Class C: Uses the first 24 bits for the Network portion leaving 8 bits for host IDs. The three leftmost bits are set to “110”.

Note: The range of Class A is actually 1-126 because 0.x.x.x and 127.x.x.x are reserved.

With these classes, a computer/device can look at the first three bits of any IP address and determine what class it belongs to. For example, the 192.168.1.250 IP address clearly falls into the Class C range.

Looking at the Host ID portion of the classes, we can determine how many hosts (or number of individual IP addresses) a network in each class will support. For example, a Class C network will ideally support up to 256 host IDs i.e. from 00000000 (decimal 0) to 11111111 (decimal 255). However, two of these addresses cannot be assigned to hosts because the first (all 0s) represents the network address while the last (all 1s) represents the broadcast address. This leaves us with 254 host IDs. A simple formula to calculate the number of hosts supported

Explanation: Final answer is Start address: 192.168.58.0 + 1 = 192.168.58.1

End address: 192.168.58.16 – 2 = 192.168.58.14

Broadcast address: 192.168.58.16 – 1 = 192.168.58.15

7 0
2 years ago
Match each of the following steps of SDLC development to its position in the development process.
Arisa [49]

Answer:

Step One - problem/opportunity identification  (V)

Step Two - Analysis (III)

Step Three - Design (II)

Step Four - Development (I)

Step Five - Testing and Installation (IV)

Explanation:

In the field of software development, or systems engineering, SDLC which refers to software development cycle refers to a systematic way of building software applications, it shows unique stages with the outcome of each stage dependent on the previous, step has a unique task which range from the planning, analysis, development, testing and installation of the information system.

5 0
3 years ago
On an XBOX 360, what does it mean if you get 4 red rings on your console?
Hitman42 [59]

Answer:

C. This happened to me.

Explanation:

4 0
3 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
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