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juin [17]
3 years ago
9

How do you write the year two-thousand-fourteen as a Roman numeral?

Mathematics
1 answer:
faust18 [17]3 years ago
6 0

Answer:

MMXIV

Step-by-step explanation:

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Solve for v -3+2v=-7
erma4kov [3.2K]

Answer:

therefore the value of V=-6

6 0
3 years ago
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What is the distance between A and B? Round your answer to the nearest tenth.
Anna35 [415]

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what are the numbers

Step-by-step explanation:

3 0
2 years ago
Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. 8cotθ + 3 = 5
galina1969 [7]

<u><em>Answer:</em></u>

θ = 76°

<u><em>Explanation:</em></u>

<u>The given equation is:</u>

8 cotθ + 3 = 5

8 cotθ = 5-3

8 cotθ = 2

cot θ = \frac{2}{8} = \frac{1}{4}

<u>Now, we find θ</u>

We know that the cot function is the inverse of the tan function.

The tan of an angle is positive in the first and third quadrants, therefore, the cot will be <u>positive</u> in the <u>first and third quadrants</u> as well

<u>Now, we are given the condition:</u>

0° ≤ x ≤ 90°

<u>Therefore, we know for sure that our angle is in the first quadrant</u>

θ = cot⁻¹(\frac{1}{4}) = 75.96° = 76° to the nearest degree

Hope this helps :)

5 0
3 years ago
$3000 deposit that earns 6% annual interest compounded quarterly ​
Lostsunrise [7]
Your interest would be $184.9 for 1 year so your total amount would be $3184.09
7 0
3 years ago
6 times the sum of 3 consecutive odd intergers is -18
Lyrx [107]
The answer: The 3 (three) consecutive odd integers are: -3, -1, 1.
_____________________________________________
Explanation:
_______________
To represent 3 (three consecutive odd integers):
____________________________________
Let "x" be the first odd integer.
____________________________________
Let "(x+2)" be next consecutive odd integer.
____________________________________
Let "(x+4") be the third odd integer.
____________________________________
The sum of these three consecutive odd integers:
__________________________________________
x + (x + 2) + (x + 4) = x + x + 2 + x + 4 = 3x + 6 ;
_________________________________________
Six ("6") times the sum of these 3 (three) consecutive odd integers =
_________________
6*(3x+6) = 6(3x + 6) = -18 (as given in the problem).
_____________________________________________
Given: 6(3x + 6) = -18 ; We can divide EACH SIDE of the equation by "6", to cancel the "6" on the left-hand side into a "1"; 
__________________________________________
{6(3x + 6) } / 6 = -18 / 6 ;  to get:
________________________________________
3x + 6 = -3 ; Now, we can subtract "6" from EACH SIDE of the equation:
__________________________________
3x + 6 - 6 = -3 - 6 ; to get:
__________________________________
3x = -9 ; Now, we can divide EACH SIDE of the equation by "3"; to isolate "x" on one side of the question; and solve for "x" ;
___________________________________
3x / 3 = -9 / 3 ;  x = - 3 ;
_____________________
Remember, from above:
__________________________
Let "x" be the first odd integer.  We know that "x = -3".
         Is this an odd integer? Yes!
____________________________________
Let "(x+2)" be next consecutive odd integer.  So (x+2) = (-3+2) = -1.
        Is this an odd integer? Yes!  Is this "{-1}" the next consecutive odd integer with respect to "{-3}"? Yes!
____________________________________
Let "(x+4") be the third odd integer. So (x+4) = (-3+4) = 1.
       Is this an odd integer? Yes!  Is this "{1"} the next consecutive odd integer with respect to "{-1}"? Yes!
___________________________
So, our 3 (three) consecutive odd integers are: -3, -1, 1.
___________________________
To check our work: Is 6 times the sum of our 3 consecutive odd integers, equal to "(-18)" ?

The sum of our 3 consecutive odd integers = -3 + (-1) + 1 = -3 - 1 + 1 = -3.

6 * -3 = ? -18? Yes!
___________________________





3 0
3 years ago
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