How do you write the year two-thousand-fourteen as a Roman numeral?
1 answer:
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Answer: 34%
Step-by-step explanation:
According to the Empirical rule,
About 68% of the population lies with in one standard deviation from the mean.
i.e. About 34% of the population lies above one standard deviation from the mean .
and About 34% of the population lies below one standard deviation from the mean.
Given : The distribution of the number of daily requests is bell-shaped ( i.e. Normally distribution) and has a mean of 60 and a standard deviation of 11.
i.e.
Using the Empirical Rule rule, 34% of the population of lightbulb replacement requests lies above one standard deviation from the mean .
i.e. About 34% of the population of lightbulb replacement requests lies between and
i.e. About 34% of the population of lightbulb replacement requests lies between and
i.e. About 34% of the population of lightbulb replacement requests lies between 60 and 71
Hence, the approximate percentage of lightbulb replacement requests numbering between 60 and 71 = 34%
Calculate the value of z and its probability, since with this we can know how likely it is that this will happen.
We have that the mean (m) is equal to 8.3, the standard deviation (sd) 1.2 and the sample size (n) = 15
They ask us for P (x =7.2)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (7.2 - 8.3) / (1.2 / (15 ^ (1/2))
z = -3.55
With the normal distribution table (attached), we have that at that value the approximate probability is:
P (z = -3.55) = 0.0001
The probability is 0.01 %
This affirms that the students do not sleep what the study says because the probability of this happening according to the survey is almost nil.
