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vivado [14]
3 years ago
7

If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function". C = {(9, 1

) (8, -3) (7, 5) (-5, 3)} Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3} Domain: {1, -3, 5, 3} Range: {9, 8, 7, -5} not a function
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
6 0

Answer:

<h2>Domain: {9, 8, 7, -5}</h2><h2>Range: {1, -3, 5, 3}</h2>

Step-by-step explanation:

The function is a special relationship where each input has a single output.

We have C = {(9, 1); (8, -3); (7, 5); (-5, 3)}.

It's a function:

each values of x: 9, 8, 7, -5 has one value of y: 1, -3, 5, 3.

The doimain is set os x: {9, 8, 7, -5}.

The range is set of y: { 1, -3, 5, 3}.

Sergeeva-Olga [200]3 years ago
4 0

F = {(x, y ) | x + y = 10}.

Domain: {10} Range: {10}

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Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

                                       width = 5 feet

                                       height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

x^{2} = 6^{2} + 5^{2}

x^{2} = 36 + 25

   = 61

x = \sqrt{61}

  = 7.81

let the length of the diagonal support be represented by l. So that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

l^{2} = x^{2} + 8^{2}

  = \sqrt{61} + 64

l  = \sqrt{\sqrt{61} + 64 }

  = 61 + 8

  = 69

Thus, the length of the diagonal support is 69 feet.

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3 years ago
A data set includes the following test scores: 75, 82, 84, 62, 78. The score on a retake test is 96. It the retake score replace
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What is the slope of x-axis? explain?
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kirill [66]

Answer:

Project A : $58,000

Project B: $52800

Project A should be selected as it has a higher expected profit value than project B

Step-by-step explanation:

Given the following:

PROJECT A:

Profit : ---------50000--90,000--10,000

Probability: ----0.6-------0.3--------0.1

PROJECT B:

Loss of 20,000 = -20,000 in profit terms

Profit : -----100,000--64,000--(-20,000)

Probability: ----0.1-------0.7--------0.2

Expected profit:

Profit value * probability of profit

Expected profit on project A:

[(50000*0.6)+(90000*0.3)+(10000*0.1)

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Expected profit on project B:

[(100000*0.1)+(64000*0.7)+(-20000*0.2)

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Project A should be selected as it has a higher expected profit value than project B

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