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vivado [14]
3 years ago
7

If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function". C = {(9, 1

) (8, -3) (7, 5) (-5, 3)} Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3} Domain: {1, -3, 5, 3} Range: {9, 8, 7, -5} not a function
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
6 0

Answer:

<h2>Domain: {9, 8, 7, -5}</h2><h2>Range: {1, -3, 5, 3}</h2>

Step-by-step explanation:

The function is a special relationship where each input has a single output.

We have C = {(9, 1); (8, -3); (7, 5); (-5, 3)}.

It's a function:

each values of x: 9, 8, 7, -5 has one value of y: 1, -3, 5, 3.

The doimain is set os x: {9, 8, 7, -5}.

The range is set of y: { 1, -3, 5, 3}.

Sergeeva-Olga [200]3 years ago
4 0

F = {(x, y ) | x + y = 10}.

Domain: {10} Range: {10}

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2 years ago
Solve using Substitution y = 6x - 11 -2x - 3y = -7
vladimir2022 [97]

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(2, 1)

Step-by-step explanation:

To solve by substitution, we solve one equation for one of its variables and then substitute the solved value for that variable into the other equation. Because this system of equations already has one solved for the variable, this makes our job much easier. We only need to implement the solved value for y into the other equation and solve for x.

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4 0
3 years ago
I think the answer is 12 am i correct?
vichka [17]
How did you get 12? It should be 11 because 9+2=11.
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3 years ago
Read 2 more answers
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