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Helen [10]
4 years ago
12

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives th

em to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?
A 1/18

B 1/15

C 2/11

D 1/4
Mathematics
1 answer:
Gwar [14]4 years ago
5 0

Answer:

B 1/15

Step-by-step explanation:

This is non-replacement choosing, so no matter which order is that (cashew-pecan or pecan-cashew) the probability is either

1 / 6 x 2 / 5  or 2 / 6 x 1 / 5  = 2/30 = 1/15

You might be interested in
e hypothesis are as follows:H0:m0:5vs.H1:m>0:5. Suppose that the null hypothesis is not rejected and that thereal truth is th
Pani-rosa [81]

Answer:

The null hypothesis is not rejected  and hence Type II error occurred

Step-by-step explanation:

Here

The null hypothesis is as follows

H0 = Mean = 0.5

The alternate hypothesis is as follows -

H1 = Mean >0.5

For Type I error = The Null hypothesis is rejected if null hypothesis is actually true

Type II error =The Null hypothesis is not rejected when the null hypothesis is not true but is false.  

Here, the null hypothesis is not rejected  and hence Type II error occurred

5 0
3 years ago
Which of the following in an identity?
sammy [17]
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
5 0
3 years ago
Time spent fishing and the amount of bait in the bucket
Pani-rosa [81]
Is this a math problem? I don’t see a picture.
7 0
3 years ago
Read 2 more answers
Factorise b^2 + 7b + 10
deff fn [24]

Step-by-step explanation:

b²+7b+10

Common factors are 5,2

b²+7b+10

b²+2b+5b+10

b(b+2)+5(b+2)

(b+2)(b+5)

Hope it helps.✨✨

4 0
2 years ago
HELLPPPPPPPPPPPP,,,,,,,,,,,
zalisa [80]

Answer:

#6 is D

#7 is A

Step-by-step explanation:

#6

-1/3(6x+15)-3

Distribute the -1/3

-1/3 times 6x is -2x

-1/3 times 15 is -5

-2x-5-3

-2x=8

#7

-12z-5z=85

COmbine like terms

-17z=85

Divide both sides by -17

z=-5

3 0
3 years ago
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