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GaryK [48]
3 years ago
6

How can you solve problems involving percents

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0
You could set up a proportion. For example, what is 20% of 40
is     %
--- = ----
of    100
is/40=20/100=1/5
5*8=40
8 would be the answer.
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Jacob and Ayden work at a dry cleaners ironing shirts. Jacob can iron 25 shirts per hour, Ayden can iron 35 shirts per hour. Ayd
Anestetic [448]

Answer:

jacob ironed 100 shirts

ayden ironed 280 shirts

Step-by-step explanation:

jacob ironed for 4 hours and ayden for 8 hours

5 0
3 years ago
ANSWER IF YOU KNOW THE ANSWER!!! I WILL GIVE BRAINLIEST BTW!!!!!!!!!!!!!
AURORKA [14]

im pretty sure its c

7 0
2 years ago
Read 2 more answers
Someone please help. i will mark as brainliest if right :)
DIA [1.3K]

Answer:

The other factor is 5x-2

Step-by-step explanation:

Using the factorisation method:

Two numbers that multiply to give -10 and add to give +3:

+5 and -2

5x^{2} +5x-2x-2

5x(x+1) -2(x+1)

(x+1)(5x-2)

So the other factor is 5x-2

I'm not sure about the second part of the question but I hope you understood how to deal with the first part.

5 0
2 years ago
An incentive clause in Barry Bonds contract allows for a 3.4% bonus if he hits over 719 home runs in this season. His contract i
N76 [4]
The bonus would be worth $493,000.

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3 0
3 years ago
Read 2 more answers
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
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