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ycow [4]
4 years ago
13

You have the set (0,5) (2,7) (3,11) (7,4) (10,5). If you added (2,1) to the set, why would it no longer be a function?

Mathematics
1 answer:
brilliants [131]4 years ago
3 0

Answer:

No, it would no longer be function.

Step-by-step explanation:

Because then there would be two different y values for the x value 2.

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Miltiply and simplify (6x - 1)(2x +3)
seropon [69]

Answer:

\Huge \boxed{12x^2 +16x-3}

Step-by-step explanation:

(6x - 1)(2x +3)

Expand brackets using the <em>FOIL</em> method.

6x(2x +3)-1(2x+3)

12x^2 +18x-2x-3

Combine like terms.

12x^2 +16x-3

6 0
3 years ago
Read 2 more answers
21. 13/4 x 42/9 =<br> O<br> A. 132/18<br> B. 64/9<br> O<br> C. 77/18<br> D. 41/6<br> Worth 2 points
ANTONII [103]
Hi! 13/4 X 42/9 = 91/6 or 91/6 ls there any other options to choose from?
4 0
3 years ago
– За + 8 = 14<br> what’s the answer
LenKa [72]

Answer:

a = -2

Step-by-step explanation:

1. 14- 8 = 6

2. 6/-3 = -2

7 0
4 years ago
Read 2 more answers
Need help ASAP
Tresset [83]

Answer:

upper left

Step-by-step explanation:

The generic equation for a circle centered at (h, k) with radius r is ...

(x -h)^2 +(y -k)^2 = r^2

Comparing that equation to the one you have, you can see that ...

-h = 0

-k = +3

r^2 = 9

Then you have (h, k) = (0, -3) and a radius of 3.

The circle has its center on the y-axis 3 units below the x-axis and just touches the x-axis. This is a description of the graph at upper left.

4 0
3 years ago
Solve this problem please!!
zavuch27 [327]

if I know how to do this I this it's y27 oh I know I wrong But it was worth a try right

Step-by-step explanation:

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7 0
3 years ago
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